One at 100,18 one at 200,14 one at 150,15 one at 125,20 and one at 225,12
The smallest is 6
Three consecutive integers
X. Smallest 6
X+1. 7
X+2. Largest 8
X(X+1)= 4(X+2)+10
X^2+X= 4x+8+10
X^2+X-4x-18=0
X^2-3x-18=0
( X+3)(X-6)
X=-3. X=6
Don't use the negative
Check 6(7)= 4(8)+10
42=42
For A well I can't do a graph ,but to do it you would start at 50 going up 25 each week
For B it would be 300 because 25×10=250 plus the 50 from his grandmother he would have 300
Answer:
B
Step-by-step explanation:
distribute 1/2 into 2x and 4, if both sides match then its infinitely many solutions !
Answer:
Step-by-step explanation:
Jada is making circular invitations
we have d=12 cm, the radius r=6
she needs to find out the circumference
C=2x3.14x r
C=2x 3.14x6=37.68
180/37.68=4.77
she can make just 4 invitations
