Find B if the graph of the equation 3x=By+2 is perpendicular to the graph of 3y=-2x+4.

The sum of two negatives is greater than -23. One of the numbers is -10. What are the possible values of the other nber

san4es73 [151]

Answer:

any number > than -13 and less than zero

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

What's the proportional relationship? I've totally forgot how to do this aaa

lubasha [3.4K]

Answer: yes it has a proportional relationship

Step-by-step explanation: Well yes it is proportional because it goes through the orgin and that is what it is if it goes through the orgin (0,0) it means it has a proportional relationship hope this helped:)

6 0

3 years ago

A bean plant grows at a constant rate for a month. After 10 days, the plant is

777dan777 [17]

Answer:

B. y - 35 = 2(x - 10)

Step-by-step explanation:

The height of the plant, y, after x days could be modeled by the equation

<h3>y-y0=k(x-xo) (1),</h3><h3>where y0 was the initial height at 'x0'th. day, and k is the constant of proportionality.</h3><h3>From equation (1), k could be evaluated as follows:</h3><h3>k=(y-y0)/(x-x0) </h3><h3>From the problem statement, we may determine k by plugging in the given values, e.g. y0= 35, x0=10, y=55, x=20.</h3><h3>Thus,</h3><h3>k=(55-35)/(20-10)=2</h3><h3>Therefore, the model equation becomes</h3><h3>y-35=2(x-10)</h3><h3></h3>

6 0

4 years ago

The rate of growth of profit (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati

Alecsey [184]

Answer:

The function is $P(x) = \frac{1}{2} e^{-x^2} +0.016$

Step-by-step explanation:

From the question we are told that

The rate of growth is $P'(x) = xe^{x} - x^2$

The total profit is $P(2) =$ $25,000

The time taken to make the profit is $x = 2 \ years$

From the question

$P'(x) = xe^{-x^2}$ is the rate of growth

Now here x represent the time taken

Now the total profit is mathematically represented as

$P(x) = \int\limits {P'(x)} \, = \int\limits {xe^{-x^2}} \,$

So using substitution method

We have that

$u = - x^2$

$du = 2xdx$

So

$p(x) = \int\limits {\frac{1}{2} e^{-u}} \, du$

$p(x) = {\frac{1}{2} [ e^{-u}} +c ]$

$p(x) = {\frac{1}{2} e^{-x^2}} + \frac{1}{2} c$ recall $u = - x^2$ and let $\frac{1}{2} c = Z$

At x = 2 years

$P(x) =$ $25,000

So

Since the profit rate is in million

$P(x) =$ $25,000 = $\frac{25000}{1000000} =$ $0.025 millon dollars

So

$0.025 = {\frac{1}{2} e^{-2^2}} + Z$

=> $Z = 0.025 - {\frac{1}{2} e^{-2^2}}$

$Z = 0.016$

So the profit function becomes

$P(x) = \frac{1}{2} e^{-x^2} +0.016$

5 0

3 years ago

At track practice,Sheila worked on the long jump. Her first jump measured 3 yards, 2 feet, 8 inches. Her second jump measured 2

jolli1 [7]

The length is 19.5 feet. this is because when you add the yards, it equals 15 feet. Next, add 1 + 2 feet from the first and second jump. 10+8 inches equal 1.5 feet. Next, add 15 feet+3 feet+1.5 feet to get 19.5 feet.

7 0

3 years ago