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Lubov Fominskaja [6]
3 years ago
14

A bean plant grows at a constant rate for a month. After 10 days, the plant is

Mathematics
1 answer:
777dan777 [17]3 years ago
6 0

Answer:

B. y - 35 = 2(x - 10)

Step-by-step explanation:

The height of the plant, y, after x days could be modeled by the equation

<h3>y-y0=k(x-xo)     (1),</h3><h3>where y0 was the initial height at 'x0'th. day, and k is the constant of proportionality.</h3><h3>From equation (1), k could be evaluated as follows:</h3><h3>k=(y-y0)/(x-x0) </h3><h3>From the problem statement, we may determine k by plugging in the given values, e.g. y0= 35, x0=10, y=55, x=20.</h3><h3>Thus,</h3><h3>k=(55-35)/(20-10)=2</h3><h3>Therefore, the model equation becomes</h3><h3>y-35=2(x-10)</h3><h3></h3>

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Which statement is true about the ranges for the box plots?
agasfer [191]

Answer:

The range of the Morning box plot is the same as the range of the Afternoon box plot.

Step-by-step explanation:

Data provided in the question

Number line = 0 to 16

Morning whiskers range = 3 to 15

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Line divided = 8

Afternoon whiskers range = 4 to 16

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Based on the above information,

The morning whiskers range difference is

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And, the afternoon whiskers range difference is

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I hope this is good enough:

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The angle of depression from the top of a cliff to an ant on the ground is 35 degrees. If the ant is 280 ft from the base of the
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If x+1/x = 5 find the value of x^3 +1/x^3. pls solve​
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Answer:

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x - 5x =  - 1

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x =  \frac{1}{4}

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x {}^{3}  +  \frac{1}{x {}^{3} }

substitute x = 1/4 into the expression

( \frac{1}{4} ) {}^{3}  +  \frac{1}{( \frac{1}{4}) {}^{3}  }

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