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Mike can buy red push pins in packages of 10 and yellow push pins in packages of 12. What is the least amount of packages of eac

deff fn [24]

Answer:

6 packages of red push pins

5 packages of yellow push pins

Step-by-step explanation:

The goal is to list the multiples of 10 and 12 and find the least common multiple (LCM) to answer the question.

The multiples of 10 are 10, 20, 30, 40, 50, 60, 70, 80, 90, 100...

The multiples of 12 are 12, 24, 36, 48, 60, 72, 84, 96, 108, 120...

The first multiple that 10 and 12 have in common is 60. Therefore, Mike must buy at least 6 packages of red push pins [60 ÷ 10 = 6] and 5 packages of yellow push pins [60 ÷ 12 = 5] to have the same number of pins of each color.

5 0

4 years ago

Wilma is twice as old as Jamal, and Jamal is 3 years older than Tim. The sum of all their ages is 17.

pickupchik [31]

W = 2J
J = T + 3......T = J - 3

W + T + J = 17
2J + J - 3 + J = 17
4J - 3 = 17
4J = 17 + 3
4J = 20
J = 20/4
J = 5 <=== Jamal is 5

W = 2J
W = 2(5)
W = 10 <== Wilma is 10

T = J - 3
T = 5 - 3
T = 2 <== Tim is 2

3 0

4 years ago

Read 2 more answers

Suppose you have 8 coins and you have at least one each of a quarter, a dime, and a penny. What is the least amount of money you

Black_prince [1.1K]

41 cents one quarter one dime six pennies

4 0

3 years ago

Tickets for a school carnival cost 10$ for adult and 5 for children. last Saturday carnival sold 170 tickets worth a total of $1

riadik2000 [5.3K]

70 adults and 100 children attended the carnival.

Step-by-step explanation:

Given,

Cost of each adult ticket = $10

Cost of each child ticket = $5

Total tickets sold = 170

Total revenue generated = $1200

Let,

Number of adults = x

Number of children = y

According to given statement;

x+y=170 Eqn 1

10x+5y=1200 Eqn 2

Multiplying Eqn 1 by 10

$10(x+y=170)\\10x+10y=1700\ \ \ Eqn\ 3$

Subtracting Eqn 2 from Eqn 3

$(10x+10y)-(10x+5y)=1700-1200\\10x+10y-10x-5y=500\\5y=500$

Dividing both sides by 5

$\frac{5y}{5}=\frac{500}{5}\\y=100$

Putting y=100 in Eqn 1

$x+100=170\\x=170-100\\x=70$

70 adults and 100 children attended the carnival.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

7 0

3 years ago

you are cooking rice for p people each bag of rice serves 6 if you had 11 bags of rice what is the maximum amount of people you

wolverine [178]

The answer is 1

Work
11/6=1.833
You can serve 1.833 people? No because unfortunately, you can't feed a fraction of a person. So, you can actually only feed 1 person.

6 0

4 years ago

Read 2 more answers