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2 years ago

I need help! plsssssssssssssssss

Mathematics

1 answer:

Simora [160]2 years ago

3 0

5.5 miles per hour ig bye

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Label the dividend, divisor, and quotient in the problem 27,438 divided by 9 equals 3,048 r6.

Alika [10]

The dividend is the number being divided so the dividend is 27,438
The divisor is the one dividing the number so the divisor is 9
The quotient is your answer so you quotient is 3048

Your answer is C.

Hope this helps!

7 0

2 years ago

5<-3x+8 solve and graph the question

bearhunter [10]

Answer:

x<1

Step-by-step explanation:

5<-3x+8 ⇒3x<8-5⇒3x<3⇒x<1

3 0

2 years ago

Simplify this problem

ikadub [295]

Answer:

$\boxed{ \frac{ \sqrt[3]{ {x}^{11} } }{4} }$

Step-by-step explanation:

$= > \frac{ {x}^{4} }{ \sqrt[3]{64x} } \\ \\ = > \frac{ {x}^{4} }{ {(64x)}^{ \frac{1}{3} } } \\ \\ = > \frac{ {x}^{4} }{ ({64}^{ \frac{1}{3} } )\times ({x}^{ \frac{1}{3} } )} \\ \\ = > \frac{ {x}^{4} }{ ({( {4}^{3} )}^{ \frac{1}{3} }) \times( {x}^{ \frac{1}{3} } )} \\ \\ = > \frac{ {x}^{4} }{ ({4}^{ \cancel{3} \times \frac{1}{ \cancel{3}} } ) \times( {x}^{ \frac{1}{3} } )} \\ \\ = > \frac{ {x}^{4} }{4 {x}^{ \frac{1}{3} } } \\ \\ = > \frac{ {x}^{4 - \frac{1}{3} } }{4} \\ \\ = > \frac{ {x}^{ \frac{12 - 1}{3} } }{4} \\ \\ = > \frac{ {x}^{ \frac{11}{3} } }{4} \\ \\ = > \frac{ \sqrt[3]{ {x}^{11} } }{4}$

7 0

2 years ago

3 of 8<br> The area of a circle is 16.71cm2.<br> Find the length of the radius rounded to 2 DP.

Cerrena [4.2K]

Answer:

Radius = 2.31 cm

Step-by-step explanation:

Area of circle = 16.71 square centimeters

$\pi r^2 = 16.71 \\3.14r^2=16.71\\r^2=\frac{16.71}{3.14}\\r^2=5.32\\\sqrt{r^2}=\sqrt{5.32}\\r=2.306$

Radius of circle = 2.31 centimeter

6 0

2 years ago

The vertices of triangle PQR are P(10,-6), Q(6,2), & R(4,-1). Describe a translation that places the image of the triangle e

Gnoma [55]

Answer:

Translate 7 units up and then translate 11 units to the left.

Step-by-step explanation:

We have the triangle PQR having co-ordinates (10,6), (6,2) and (4,-1).

It is required to translate ΔPQR so that the resulting image is completely inside the 2nd quadrant.

So, for that we will apply the following sequence of translations:

1. Translate 7 units up.

This will give us the figure in the 1st quadrant having co-ordinates (10,1), (6,9) and (4,6).

2. Translate 11 units to the left

We will get the final triangle P'Q'R' with the co-ordinates P'(-1,1), Q'(-5,9) and R'(-7,6) as shown below.

5 0

2 years ago