If it's a whole number it would be 1 and of it wasn't it's .1 or .09
Answer:
p=-9
Step-by-step explanation:
132=-6+3 (1-5p)
-6+3 (1-5p)=132
-6+3 (1-5p)+6=132+6
3(1-5p)=138
3(1-5p)/3=138/3
1-5p=46
1-5p-1=46-1
-5p=45
p=-9
Step-by-step explanation:
it clearly consists of 2 rectangles and 1 triangle (as you tried correctly to point out by drawing the separating lines).
we only need to calculate all 3 areas and add them up for the total.
the area of a rectangle is
length × width
so, in our 2 cases we have
6 × 2 = 12 km²
5 × (3 + 2 + 3) = 5×8 = 40 km²
the area of a triangle is
baseline × height / 2
in case of a right-angled triangle the 2 sides enclosing the 90° angle can be used as baseline and height.
so, in our case
6 × (5 + 2 + (3 + 2 + 3 - 2)) / 2 = 6×(7 + 6)/2 = 3×13 = 39 km²
in total, the whole area is
12 + 40 + 39 = 91 km²
Surface area of box=1200 cm²
<span>Volume of box=s²h </span>
<span>s = side of square base </span>
<span>h = height of box </span>
<span>S.A. = s² + 4sh </span>
<span>S.A. = surface area or 1200 cm², s²
= the square base, and 4sh = the four 'walls' of the box. </span>
<span>1200 = s² + 4sh </span>
<span>1200 - s² = 4sh </span>
<span>(1200 - s²)/(4s) = h </span>
<span>v(s) = s²((1200 - s²)/(4s)) </span>
<span>v(s) = s(1200 - s²)/4 . </span>
<span>v(s) = 300s - (1/4)s^3</span>
by derivating
<span>v'(s) = 300 - (3/4)s² </span>
<span>0 = 300 - (3/4)s² </span>
<span>-300 = (-3/4)s² </span>
<span>400 = s² </span>
<span>s = -20 and 20. </span>
again derivating
<span>v"(s) = -(3/2)s </span>
<span>v"(-20) = -(3/2)(-20) </span>
<span>v"(-20) = 30 </span>
<span>v"(20) = -(3/2)(20) </span>
<span>v"(20) = -30 </span>
<span>v(s) = 300s - (1/4)s^3 </span>
<span>v(s) = 300(20) - (1/4)(20)^3 </span>
<span>v(s) = 6000 - (1/4)(8000) </span>
<span>v = 6000 - 2000
v=4000</span>
Answer:
-3z-11=11z^2
Step-by-step explanation:
