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Ludmilka [50]
3 years ago
7

PLS HURRY!! Look at the image below!

Computers and Technology
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer:

Line 2: for numF in [3, 5]

Line 1: for numE in [2, 6]

Line 3: print(numE, numF)

Explanation:

From the outputs, the first number of the first output is 2. This means that <em>numE in [</em><em>2</em><em>, 6]</em> would be on the first line.

The second number of the first output is 3, concluding that <em>numF in [</em><em>3</em><em>, 5]</em> is within a nested loop, meaning it would be on the second line.

This leaves <em>print(numE, numF)</em> on line 3.

We can go through the lines step by step to check if we have placed them in the correct order:

Code

for numE in [2, 6]:

 for numF in [3, 5]:

   print(numE, numF)

During the first iteration, numE = 2 and numF = 3.

Output: 2, 3

Since [3, 5] is in a nested loop, we need to finish iterating all of its numbers before numE moves to the next number, so:

numF moves to 5, numE stays at 2.

Output: 2, 5

Since we have finished iterating through [3, 5], numE moves to 6 and numF starts back at 3:

Output: 6, 3

numE still stays at 6 and numF iterates to 5 since [3, 5] is in a nested loop:

Output: 6, 5

The outputs match the outputs on the sheet, meaning we have correctly placed the code in order.

Hope this helps :)

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Answer:

Following are the statement is given below

if(updateDirection ==1) // check condition

{

++numUsers; // increments the value

}

else

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Explanation:

Following are the description of statement

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</span>
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Answer:

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Explanation:

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