Answer:
True
Explanation:
Most of the organization suffers from InfoObesity, i.e., too much data without the proper holding structure for this.
Business intelligence abbreviated as BI plays a major role in the determining the planning strategies of an organizations and serves multiple purposes which includes measurement of performance towards business objectives, quantitative analysis, data reporting and sharing, etc.
BI systems helps in eliminating InfoObesity, by manging the data and filtration of the data with proper data structure to serve specific purposes.
Answer:
B. Use a new support manager permission sets
Explanation:
According to the requirements, field level security is required so, 1st options is not suitable because it may reduce the maintenance cost but increase the risk of security.
By creating a separate page for each of the two, it will leads to increase in the maintenance cost of the system. So <u>Option C</u> is also not suitable.
Option B is more Suitable as compared to others, that <em>Create a new support manager permission set</em>, with the help of this, both of Support rep and Support manager can visualize their required information with the help of support manager permission. This solution will not compromise the security and not increase the maintenance cost.
Answer:
B and D.
Explanation:
An individual working as a network administrator is responsible for a variety of different tasks which can include the design of the network itself, security for the network, and identifying and fixing issues. This is done in order to keep the computer network up-to-date and functioning as intended within the company or organization.
Which formula contains an absolute cell reference? =SUM($B$7:$B$9)
Answer:
See explaination
Explanation:
MinMax.java
import java.util.*;
public class MinMax
{
static void MinMax(int[] arr)
{
int Min=arr[0]; // initializinf min and max with 1st value of array
int Max=arr[0];
for(int i=0;i<arr.length;i++) // iterating loop only once
{
if(arr[i]>Max) // checking max value
{
Max=arr[i];
}
if(arr[i]<Min) // checking min value
{
Min=arr[i];
}
}
System.out.println("Min Number is "+Min); //printing min value
System.out.println("Max Number is "+Max); //printing max value
}
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter N value: "); // taking n value
int n=sc.nextInt();
int[] arr=new int[n];
System.out.println("Enter N elements:"); // taking n elements into array
for(int i=0;i<n;i++)
{
arr[i]=sc.nextInt(); // each element into the array
}
MinMax(arr); // calling MinMax() method.
}
}
