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Art [367]
2 years ago
11

Help please it’s due soon ( DISTANCE IS A MISTAKE )

Mathematics
1 answer:
katrin [286]2 years ago
4 0

Answer:

speed

time

faster

greater

You can fill in these words in the blanks.

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MATH!!!
kozerog [31]

Answer:

210 Hope it helps! if you have any other questions I can help

6 0
2 years ago
If log2 5 = k, determine an expression for log32 5 in terms of k.
lukranit [14]

Answer:

log_3_2(5)=\frac{1}{5} k

Step-by-step explanation:

Let's start by using change of base property:

log_b(x)=\frac{log_a(x)}{log_a(b)}

So, for log_2(5)

log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)

Now, using change of base for log_3_2(5)

log_3_2(5)=\frac{log(5)}{log(32)}

You can express 32 as:

2^5

Using reduction of power property:

log_z(x^y)=ylog_z(x)

log(32)=log(2^5)=5log(2)

Therefore:

log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)

As you can see the only difference between (1) and (2) is the coefficient \frac{1}{5} :

So:

\frac{log(5)}{log(2)} =k\\

log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k

6 0
2 years ago
Use the distributive property to write the expression as a product<br> 10+70x
grigory [225]

Answer:

10(1+7x)

Step-by-step explanation:

Just factored out the 10.

4 0
3 years ago
Find the center and radius for the circle by the equations: x2 + y2 + 5x - y + 2 = 0.
lord [1]
X2+5x+y2-y=-2
X2+2*5x2+(5/2)^2-(5/2)^2+y2-2*y/2+(1/2)^2-(1/2)^2=-2
(x+5/2)^2+(y-1/2)^2-13/2=-2
(x+5/2)^2+(y-1/2)^2=9/2
So centre =(-5/2,1/2)
Radius=(9/2)^(1/2)
7 0
3 years ago
Y = (x + 4)2 - 1<br> Standard form
denpristay [2]

answer :

y = 2x + 7

i hope it helped

3 0
2 years ago
Read 2 more answers
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