Answer
Formula
![Circumference\ of\ circle = 2\pi r](https://tex.z-dn.net/?f=Circumference%5C%20of%5C%20circle%20%3D%202%5Cpi%20r)
where r is the radius of a circle.
As shown in the image
Diameter of the circle = 16 .3 cm
![Radius\ of\ the\ circle = \frac{16.3}{2}](https://tex.z-dn.net/?f=Radius%5C%20of%5C%20the%5C%20circle%20%3D%20%5Cfrac%7B16.3%7D%7B2%7D)
= 8.15 cm
Put in the formula
![Circumference\ of\ circle = 2\pi\times 8.15](https://tex.z-dn.net/?f=Circumference%5C%20of%5C%20circle%20%3D%202%5Cpi%5Ctimes%208.15)
As
![\pi = 3.14](https://tex.z-dn.net/?f=%5Cpi%20%3D%203.14)
![Circumference\ of\ circle = 2\times 3.14\times 8.15](https://tex.z-dn.net/?f=Circumference%5C%20of%5C%20circle%20%3D%202%5Ctimes%203.14%5Ctimes%208.15)
= 51.2 cm (approx)
Therefore the circumference of a circle is 51.2cm (approx) .
Option (D) is correct .
Answer:
1 m³
Step-by-step explanation:
first find volume of smaller cubes
V = lwh
S = 1/3*1/3*1/3
S = 1/27
find volume of large cube. there are 27 smaller cubes.
V = 27S
V = 27(1/27)
V = 1
S: volume of small cube
V: volume of large cube
Answer:
![\huge\boxed{7\ \text{inches}}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B7%5C%20%20%5Ctext%7Binches%7D%7D)
Step-by-step explanation:
As I mentioned earlier with a single side (line), rotations do not change the size of something. Only dilations do that. This goes for both lines AND shapes.
However, if the question said she dilated the piece, then yes, the length in inches would be different. However, rotation just changes the position and nothing happens to the length.
Hope this helped!
+8y and -8y cross out.
So the first one is 3x=15
Second one is 2x=10
x=5
Then plug x is one of the equations
2(5)-8y=10
10-8y=10
x=5
y=0