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3 years ago

5

A person invested $7,200 in an account growing rate allowing money to double every 8 years. How much money would be in the accou

nt after 19 years, to the nearest dollar?

1 answer:

spayn [35]3 years ago

5 0

273600 in his bank account

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Asking again because last time I didnt get an actual answer. What is the surface area of this composite figure?

Katyanochek1 [597]

Answer:

644 cm^2

Step-by-step explanation:

10*7*2+12*7*2+12*10=140+168+120=428

10*12-3*3=111

428+111=539

8*3*4+3*3=96+9=105

539+105=644

3 0

3 years ago

If a puppet requires 3/4 yard of material, how many puppets can be made from 9 yards of material?

klasskru [66]

First find out how many times 3/4 yard goes into 9. 3/4 fits into 9 twelve times, so twelve puppets can be made.

Did I help? Thank me by clicking best answer!

5 0

3 years ago

Read 2 more answers

If 3 p +3 4 =90

klemol [59]

3p + 34 = 90
3p = 90 - 34
3p = 56
p = 56/3
p = 18.67 (thats rounded)

2r + 44 = 76
2r = 76 - 44
2r = 32
r = 32/2
r = 16

53 + 6s = 1421
6s = 1421 - 53
6s = 1368
s = 1368/6
s = 228

" the product " means multiply
p x r x s = 18.67 x 16 x 228 = 68,108.16

8 0

3 years ago

HELP NEEDED ASAP!! Amani computed in a two-way table the relative frequencies of sales of homes listed with two different real e

guajiro [1.7K]

The answer is c.

When you look at the data, in the first column, the frequency of sales of both are similar. Even the second column shows similar data. Association is determined if there is a significant difference between the data in each column/row depending on what you are aiming to answer.

In this case, we look at it per column because you want to compare the frequencies of sales of each company which are aligned by columns. So we know to look at the columns and not the rows.

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3 years ago

Read 2 more answers

A national study report indicated that 20.9% of Americans were identified as having medical bill financial issues. What if a ne

Alenkasestr [34]

Answer:

The p-value for this test is 0.22065.

Step-by-step explanation:

We are given that a national study report indicated that 20.9% of Americans were identified as having medical bill financial issues.

A news organization randomly sampled 400 Americans from 10 cities and found that 90 reported having such difficulty.

<u><em>Let p = proportion of Americans who were identified as having medical bill financial issues in 10 cities.</em></u>

SO, Null Hypothesis, $H_0$ : p $\leq$ 20.9% {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is less than or equal to 20.9%}

Alternate Hypothesis, $H_A$ : p > 20.9% {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is more than 20.9% and is more severe}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 400 Americans from 10 cities who were found having such difficulty = $\frac{90}{400}$ = 0.225 or 22.5%

n = sample of Americans = 400

So, <u><em>test statistics</em></u> = $\frac{0.225-0.209}{{\sqrt{\frac{0.225(1-0.225)}{400} } } } }$

= 0.77

<u></u>

<u>Now, P-value of the test statistics is given by the following formula;</u>

P-value = P(Z > 0.77) = 1 - P(Z $\leq$ 0.77)

= 1 - 0.77935 = 0.22065

5 0

3 years ago