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kirza4 [7]
3 years ago
8

A fair coin is tossed four times. What is the probability that the number of heads appearing on the first two tosses is equal to

the number of heads appearing on the second two tosses
Mathematics
1 answer:
alekssr [168]3 years ago
8 0

Answer: 3/8

Step-by-step explanation:

Since it is a fair coin, then generally, P(Head) = P(Tail) = ½

And since we've been asked to find the probability that the number of heads in the first two tosses be equal to the number of heads in the second two tosses, tossing a fair coin four times, the possible outcomes of having equal number of heads in first two tosses and second two tosses becomes:

[HHHH] or [HTHT] or [THTH] or [TTTT] or [HTTH] or [THHT]

=[½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½]

=1/16 * 6

=6/16

=3/8.

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Step-by-step explanation:

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6 0
3 years ago
The perimeter of the square can be represented by the expression 36x+44 robin wants to write an equivalent expression for the pe
sukhopar [10]

Answer:

4  (9 x + 11) is an equivalent expression for the perimeter that shows the side length of the square is  (9 x + 11).

Step-by-step explanation:

Here, given The perimeter of the square  = (36 x+44)

Now,as we know :

PERIMETER OF SQUARE = 4 x ( SIDES)

Simplifying the perimeter expression.

Take 4 common out of the expression (36 x+44), we get:

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⇒ Perimeter of the square  =  4 x  (9 x + 11)

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⇒ Each Side = (9 x + 11)

Hence, 4 x (9 x + 11) is an equivalent expression for the perimeter that shows the side length of the square is  (9 x + 11).

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3 years ago
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3 years ago
Mia's checking account balance is overdrawn by $52.65.
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Hope this helped you out! :-)
6 0
3 years ago
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