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kirza4 [7]
3 years ago
8

A fair coin is tossed four times. What is the probability that the number of heads appearing on the first two tosses is equal to

the number of heads appearing on the second two tosses
Mathematics
1 answer:
alekssr [168]3 years ago
8 0

Answer: 3/8

Step-by-step explanation:

Since it is a fair coin, then generally, P(Head) = P(Tail) = ½

And since we've been asked to find the probability that the number of heads in the first two tosses be equal to the number of heads in the second two tosses, tossing a fair coin four times, the possible outcomes of having equal number of heads in first two tosses and second two tosses becomes:

[HHHH] or [HTHT] or [THTH] or [TTTT] or [HTTH] or [THHT]

=[½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½] + [½*½×½*½]

=1/16 * 6

=6/16

=3/8.

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Answer:

a) The 99% CI for the true proportion of voters who prefer the Republican candidate is (0.3658, 0.6001). This means that we are 99% sure that the true population proportion of all voters who prefer the Republican candidate is (0.3658, 0.6001).

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Step-by-step explanation:

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In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

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n = 120, \pi = \frac{58}{120} = 0.4833

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