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3 years ago

10

A baseball team played 154 regular season gamesThe ratio the tumber games they the games they lost 2/5 How many games they many

games did they lose?I WILL MARK THE BRAINEST!!!

1 answer:

AURORKA [14]3 years ago

5 0

Answer:

61

Step-by-step explanation:

154 * 2/5 = 61.6

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15 1/4 acres of land are to be divided into lots of at least 2/3 acres each What is the maximum number of lots that can be creat

Sholpan [36]

Well, if you want the maximum number of splits, then you want to make
each individual split as small as possible.
That's 2/3 acre. How many will that give you ?

(15 and 1/4) divided by (2/3)

= (15.25) / (0.666...) = 22.875 pieces .

The maximum number of 2/3-acre lots you can sell is 22 lots.

Then you have 58.3% of an acre of land left over that you can't sell
because it's less than 2/3 acre. Sadly, that 58.3% of an acre is just
about the size of the lot that I've been living n for almost 30 years.
You really know how to rub it in, dontcha !

5 0

3 years ago

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Choose the polynomial written in standard form.

Semenov [28]

Answer:

$x^4 + 4x^3 + 10x$

Step-by-step explanation:

A polynomial written in decreasing order of the degree of its monomials ( or single term ) is called its standard form,

In polynomial,

$x^2 + 4x^4 + 10x^6$ ,

Degrees are written in increasing order,

⇒ It is not written in standard form,

In polynomial,

$x^4 + 4x^3 + 10x$ ,

Degrees are written in decreasing order,

⇒ It is written in standard form,

In polynomial,

$x^7 + 4x^3 + 10x^4$ ,

There is no order of degrees,

⇒ It is not written in standard form,

In polynomial,

$x^6 + 4x^3 + 10x^7$ ,

There is no order of degrees,

⇒ It is not written in standard form,

4 0

3 years ago

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the populatipn of a school of fish increases at a rate of 18% a Month. There are currently 500 fish in the school.

ruslelena [56]

You first must find the 18% of the fish population.

You multiply 500 by .18 . You are supposed to get 90.

90 is the 18% fish increase.

Then you just add 500 + 90 and you will get 590 fish that are now in the school.

8 0

3 years ago

I would love some help here

solniwko [45]

Answer:

first

Step-by-step explanation:

3 0

3 years ago

PLEASE HELP I DO NOT UNDERSTAND AT ALL ITS PRECALC PLEASE SERIOUS ANSWERS

Elina [12.6K]

You want to end up with $A\sin(\omega t+\phi)$ . Expand this using the angle sum identity for sine:

$A\sin(\omega t+\phi)=A\sin(\omega t)\cos\phi+A\cos(\omega t)\sin\phi$

We want this to line up with $2\sin(4\pi t)+5\cos(4\pi t)$ . Right away, we know $\omega=4\pi$ .

We also need to have

$\begin{cases}A\cos\phi=2\\A\sin\phi=5\end{cases}$

Recall that $\sin^2x+\cos^2x=1$ for all $x$ ; this means

$(A\cos\phi)^2+(A\sin\phi)^2=2^2+5^2\implies A^2=29\implies A=\sqrt{29}$

Then

$\begin{cases}\cos\phi=\frac2{\sqrt{29}}\\\sin\phi=\frac5{\sqrt{29}}\end{cases}\implies\tan\phi=\dfrac{\sin\phi}{\cos\phi}=\dfrac52\implies\phi=\tan^{-1}\left(\dfrac52\right)$

So we end up with

$2\sin(4\pi t)+5\cos(4\pi t)=\sqrt{29}\sin\left(4\pi t+\tan^{-1}\left(\dfrac52\right)\right)$

8 0

3 years ago

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