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Daniel [21]
3 years ago
5

I don't know how to write this can someone please help

Mathematics
2 answers:
I am Lyosha [343]3 years ago
7 0

Answer:

50

Step-by-step explanation:

2(9+16)=2*25=50

velikii [3]3 years ago
4 0

Answer:

three square times four square multiplied by two

How to solve + answer:

3 square = 3 x 3 = 9

4 squared = 4 x 4 = 16

9 + 16 = 25

25 x 2 = 50

50 is your answer

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Notice that the rule for each animal involves counting the number of chirps in different time intervals. For the Brookdale crick
shusha [124]
B= 15c maybe I think
8 0
3 years ago
A delivery truck driver charges a fixed base price of $6 for 2 miles. After 2 miles, he charges an additional $2 for every mile.
Amanda [17]

Answer:

B

Step-by-step explanation:

That delivery truck driver charges a fixed base price of $6 for 2 miles.

After 2 miles, he charges an additional $2 for every mile and after 6 miles, he charges an additional $4 for every mile.

We need to describe the cost of the delivery truck between 1 mile and 2 miles.

In the given graph x-axis represents the distance in miles and y-axis represents the cost in dollars.

From the given graph it is clear that the value of function is constant between x=1 and x=2.

It means the cost of the delivery truck between 1 mile and 2 miles is constant.

Therefore, the correct option is B.

5 0
3 years ago
What is the answer with work please
frozen [14]
For 12, the answer would be Y is greater than or equal to 8. If you subtract 193 from both sides of the inequality, you are left with y and 201-193=8. So the overall inequality would look like y>=8. Therefore, you would shade from 8, and everything greater than 8, with a closed circle.
6 0
3 years ago
1] If 221ₓ= 25₁₀ find X<br> 2] if 3ₓ + 34ₓ - 40ₓ = 0 find x<br> 3] if 23ₓ = 1111₂ find x
Olin [163]

1.

2\cdot x^2+2\cdot x^1+1\cdot x^0=25\\2x^2+2x+1=25\\2x^2+2x-24=0\\x^2+x-12=0\\x^2+4x-3x-12=0\\x(x+4)-3(x+4)=0\\(x-3)(x+4)=0\\x=3 \vee x=-4

The base can't be negative, therefore x=3.

2.

3\cdot x^0+3\cdot x^1+4\cdot x^0-4\cdot x^1+0\cdot x^0=0\\3+3x+4-4x=0\\x=7

3.

2\cdot x^1+3\cdotx^0=1\cdot 2^3+1\cdot2^2+1\cdot2^1+1\cdot2^0\\2x+1=8+4+2+1\\2x=14\\x=7

5 0
2 years ago
1. -5|y|=-25 2. 9|y|=27
Mademuasel [1]
What they are in the absolute symbols ( |x| ) the number is always positive
1. |y|= 5
2. |y|= 3
8 0
4 years ago
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