We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
$5.50 x 2 is $11.00
$2.50 x 2 is $5.00
$11 plus $5 is $16
it costs $16 to rent a pair of skates for 4 hours
Hello,
What we want to do is multiply 1/6 by each value within the parentheses individually.
So, it would be:
(1/6) * (18x) = 3x
(1/6) * (-24) = -4
Together, this would be 3x-4.
Hope this helps!
The correct answer is one doughnut cost 2$