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kicyunya [14]
3 years ago
11

Lila collected the honey from 3 of her beehives. From the first hive, she collected 2/3 gallons of honey. The last two hives yie

lded 1/4 gallon each. (A) How many gallons of honey did Lila collect in all?
Mathematics
2 answers:
attashe74 [19]3 years ago
6 0

Answer:

The Answer for you guys does notknow thw answer is 1234567890/1234567890

Step-by-step explanation:

goodluck

djverab [1.8K]3 years ago
3 0

Answer:

Lila need to get her ahh away from beehives

Step-by-step explanation:

SHE SHOULD TAKE HER Ahh TO THE NORMAL STORE IF SHE WANT SUM HONEY AND STOP FW DA BEES...

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For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.
nordsb [41]

Answer:

<h3>For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.</h3>

By De morgan's law

(A\cap B)^{c}=A^{c}\cup B^{c}\\\\P((A\cap B)^{c})=P(A^{c}\cup B^{c})\leq P(A^{c})+P(B^{c}) \\\\1-P(A\cap B)\leq  P(A^{c})+P(B^{c}) \\\\1-P(A\cap B)\leq  1-P(A)+1-P(B)\\\\-P(A\cap B)\leq  1-P(A)-P(B)\\\\P(A\cap B)\geq P(A)+P(B)-1

which is Bonferroni’s inequality

<h3>Result 1: P (Ac) = 1 − P(A)</h3>

Proof

If S is universal set then

A\cup A^{c}=S\\\\P(A\cup A^{c})=P(S)\\\\P(A)+P(A^{c})=1\\\\P(A^{c})=1-P(A)

<h3>Result 2 : For any two events A and B, P (A∪B) = P (A)+P (B)−P (A∩B) and P(A) ≥ P(B)</h3>

Proof:

If S is a universal set then:

A\cup(B\cap A^{c})=(A\cup B) \cap (A\cup A^{c})\\=(A\cup B) \cap S\\A\cup(B\cap A^{c})=(A\cup B)

Which show A∪B can be expressed as union of two disjoint sets.

If A and (B∩Ac) are two disjoint sets then

P(A\cup B) =P(A) + P(B\cap A^{c})---(1)\\

B can be  expressed as:

B=B\cap(A\cup A^{c})\\

If B is intersection of two disjoint sets then

P(B)=P(B\cap(A)+P(B\cup A^{c})\\P(B\cup A^{c}=P(B)-P(B\cap A)

Then (1) becomes

P(A\cup B) =P(A) +P(B)-P(A\cap B)\\

<h3>Result 3: For any two events A and B, P(A) = P(A ∩ B) + P (A ∩ Bc)</h3>

Proof:

If A and B are two disjoint sets then

A=A\cap(B\cup B^{c})\\A=(A\cap B) \cup (A\cap B^{c})\\P(A)=P(A\cap B) + P(A\cap B^{c})\\

<h3>Result 4: If B ⊂ A, then A∩B = B. Therefore P (A)−P (B) = P (A ∩ Bc) </h3>

Proof:

If B is subset of A then all elements of B lie in A so A ∩ B =B

A =(A \cap B)\cup (A\cap B^{c}) = B \cup ( A\cap B^{c})

where A and A ∩ Bc  are disjoint.

P(A)=P(B\cup ( A\cap B^{c}))\\\\P(A)=P(B)+P( A\cap B^{c})

From axiom P(E)≥0

P( A\cap B^{c})\geq 0\\\\P(A)-P(B)=P( A\cap B^{c})\\P(A)=P(B)+P(A\cap B^{c})\geq P(B)

Therefore,

P(A)≥P(B)

8 0
3 years ago
Please help me, I need a math expert
Luda [366]
<u>Sampe : Total</u>
25        :   750
(÷25)       (÷25)
  1         :    30
( x7)         ( x7)
  7        :    210

Answer:  (a) There is a total of 210 orange cakes made on Monday.

The sample is 5 when corrected to the nearest whole number.
⇒Smallest possible number is 4.5

Total orange cakes baked on Tuesday = 4.5 x 30 = 135

P(Orange Cake)  = 135/750 = 9/50

Answer: (b) The probability is 9/50

8 0
3 years ago
Which statement is true about the end behavior of the graphed function?
tatyana61 [14]

The <em><u>correct answer</u></em> is:

A) as the x-values go to positive infinity, the functions values go to negative infinity.  

Explanation:

We can see in the graph that the right hand portion continues downward to negative infinity.  The right hand side of the graph is "as x approaches positive infinity," since x continues to grow larger and larger.  This means as x approaches positive infinity, the value of the function approaches negative infinity.

8 0
3 years ago
Read 2 more answers
In ACME PUBLISHING SWEEPSTAKES, the chance of winning a car is 1 in 1,000. What percent of tickets to ACME PUBLISHING SWEEPSTAKE
Yuri [45]

Answer:

0.1% of tickets to ACME PUBLISHING SWEEPSTAKES win a car

Step-by-step explanation:

Given :The chance of winning a car is 1 in 1,000.

To Find : What percent of tickets to ACME PUBLISHING SWEEPSTAKES win a car?

Solution:

The chance of winning a car is 1 in 1,000.

The percent of tickets to ACME PUBLISHING SWEEPSTAKES win a car:

=\frac{1}{1000} \times 100

=\frac{1}{10}

=0.1\%

Hence 0.1% of tickets to ACME PUBLISHING SWEEPSTAKES win a car.

8 0
3 years ago
An obtuse triangle has two angles 45 n 18 ,and a third unknown angle theta what's the value of the unknown angle​
zlopas [31]

<u>Answer:</u>

An obtuse triangle has two angles 45 and 18. The value of the unknown angle is 117^{\circ}

<u>Solution:</u>

Given that two angles of an obtuse triangle is 45 and 18.  

Third angle is θ  

We are asked to find the value of third unknown angle theta

According to <em>angle sum property of triangle</em>, sum of three angles of triangle is 180^{\circ}

This means in our case sum of 45, 18 and θ should be 180^{\circ}

\begin{array}{l}{=>45+18+\theta=180} \\ {=>\theta=180-63=117^{\circ}}\end{array}

Hence value of unknown third angle of an obtuse triangle is 117^{\circ}

7 0
3 years ago
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