According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:
Here, n is equal to 66 and by substituting the value to the equation we get:
k = 7.0444
k ≈ 7
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Answer:
-15
Step-by-step explanation:
-3 + -12 = -15
slope intercept form is y=mx+b
To find this from standard form you need to remove x to the other side. To do this you need to add 5x to both sides. You will end up with 3y=5x+6. To yet the y by itself you need to divide everything in the equation by 3. You would end up with y=5/3x +2 which is the equation in slope intercept form
Answer:
28m⁷n⁵
Step-by-step explanation:
You would first multiply 14 by 2. You would then multiply (which is really addition when it comes to exponents) your like-term exponents.
(14m²n⁵)(2m⁵) =28m⁷n⁵
14(2) = 28
m² + m⁵=m⁷
n⁵ + 0 = n⁵
Answer:
58
Step-by-step explanation:
1. let x be the unknown number
2. make an expression
x + 26/12 = 7/1
3. cross multiply
x +26 × 1 = x + 26
12 × 7 = 84
x + 26 = 84
4. move variables on one side and numbers on other side of the equal sign
x + 26 = 84
- 26 -26
x = 58
