If someone doesn’t help me I will stab myslef

sergiy2304 [10]

They are vertical angles and congruent angles.

8 0

3 years ago

A rectangle has a length of 11 meters less than 10 times its width. If the area of the rectangle is 9888 square meters, find the

kobusy [5.1K]

Step-by-step explanation:

The Length ,

L

=

284

f

t

.

Explanation:

Given:

Rectangle

Area,

A

=

8804

f

t

2

let W bet he width of the rectangle

L be the length of the rectangle

L

=

10

W

−

26

E

q

u

a

t

i

o

n

1

substitute to

e

q

u

a

t

i

o

n

2

A

=

(

L

)

(

W

)

e

q

u

a

t

i

o

n

2

A

=

(

10

W

−

26

)

(

W

)

8804

=

(

10

W

−

26

)

(

W

)

factor

8804

=

2

(

5

W

−

13

)

(

W

)

divide both sides by 2

4402

=

(

5

W

−

13

)

(

W

)

4402

=

5

W

2

−

13

W

transposing 4402 to the right side of the equation

0

=

5

W

2

−

13

W

−

4402

by quadratic formula

W

=

−

(

−

13

)

+

√

(

−

13

)

2

−

4

(

5

)

(

−

4402

)

2

(

5

)

W

=

[

13

+

√

169

+

88040

]

10

W

=

13

+

(

√

88209

)

10

W

=

13

+

297

10

W

=

310

10

W

=

31

ft

Thus ,

L

=

10

W

−

26

=

10

(

31

)

−

26

L

=

284

f

t

.

answer

W

=

−

(

−

13

)

−

√

−

(

−

13

2

)

−

4

(

5

)

(

−

4402

)

2

(

5

)

this is discarded since this will yield a negative

8 0

3 years ago

HELP ME PLZ ASAPPPPPP

boyakko [2]

Answer:

$(x,y) =(-4,-3)$ --- Vertex

$x = -4$ --- Axis of symmetry

Step-by-step explanation:

Given

$y = -6(x + 4)^2 - 3$

Solving (a): The vertex

For an equation written in

$y = a(x - h)^2 + k$

The vertex is:

$(x,y) = (h,k)$

By comparison:

$y = a(x - h)^2 + k$ and $y = -6(x + 4)^2 - 3$

$-h =4$ $k = -3$

$h =-4$ $k = -3$

So, the vertex is:

$(x,y) =(-4,-3)$

Solving (b): The axis of symmetry

For an equation written in

$y = a(x - h)^2 + k$

The axis of symmetry is:

x = h

In (a):

$h =-4$

So:

$x = -4$

5 0

3 years ago

Sean bought a laptop and a printer.

stealth61 [152]

Answer:

£102.04

Step-by-step explanation:

£1250 - £1100 = £150

printer sold for £150

£150 = 147%

1% = 1.0204

100% = 102.0408

to 2dp = £102.04

3 0

3 years ago

What is the sum of all of the perfect squares between

Nonamiya [84]

Answer:

(-138) is the answer.

Step-by-step explanation:

Perfect square numbers between 15 and 25 inclusive are 16 and 25.

Sum of perfect square numbers 16 and 25 = 16 + 25 = 41

Sum of the remaining numbers between 15 and 25 inclusive means sum of the numbers from 17 to 24 plus 15.

Since sum of an arithmetic progression is defined by the expression

$S_{n}=\frac{n}{2}[2a+(n-1)d]$

Where n = number of terms

a = first term of the sequence

d = common difference

$S_{8}=\frac{8}{2} [2\times 17+(8-1)\times 1]$

= 4(34 + 7)

= 164

Sum of 15 + $S_{8}$ = 15 + 164 = 179

Now the difference between 41 and sum of perfect squares between 15 and 25 inclusive = $41-179$

= -138

Therefore, answer is (-138).

7 0

3 years ago