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Ksenya-84 [330]
3 years ago
15

Use diagram to answer 3(x+6)=30

Mathematics
2 answers:
Alja [10]3 years ago
6 0
The answer is 4
Plug in method

3 (4)+6 =30 plug in value for x
3(4)+3(6) =30 distributive prop.
12+18=30 equals 30
Katyanochek1 [597]3 years ago
5 0

Answer:

Step-by-step explanation:

3x + 18 = 30

3x + 18 -18 = 30 - 18

3x = 12

x = 4

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The graph of a certain quadratic function does not cross the x-axis. Which of the following are possible values for the discrimi
irinina [24]
The graph of a quadratic function does not cross the x-axis if the discriminant has negative value.
Answers:
C ) -25
D ) -7
3 0
3 years ago
I'm confused on how to find x​
azamat

Answer:

x = 2

Step-by-step explanation:

Since this is a 45-45-90 triangle, the 2 legs will be the same, meaning that y will also be \sqrt2.

We can then solve for x using the Pythagorean theorem:

\sqrt2^2+\sqrt2^2=x^2\\2+2=x^2\\4=x^2\\x=2

Or, we could use a quicker approach: if the triangle is a 45-45-90 triangle, the hypotenuse will be \sqrt2 times the length of 1 leg. It essentially does the same thing; it's just faster so you could save time on tests.

7 0
2 years ago
Right now, I am adding fractions, what number can you use to simplify 55/48?
Brrunno [24]

You can't its already simplified


5 0
3 years ago
Read 2 more answers
Does anyone know the answer for this question? No links
PIT_PIT [208]

Answer:

3,2 like I show just don't put and symbols like it said in the question

7 0
3 years ago
Help please, I need it
OlgaM077 [116]

Answer:

  2)  c)  (x-3)² + (y+2)² = 25

  5)  x^2 +y^2 -8x -16y +54 = 0

  6)  x^2 +y^2 -10x -12y +36 = 0

Step-by-step explanation:

2) The standard form equation for a circle is ...

  (x -h)^2 +(y -k)^2 = r^2

You are given the center: (h, k) = (3, -2) and a point on the circle. So, the equation will be ...

  (x -3)^2 +(y +2)^2 = r^2

Since we know a point on the circle we know that ...

  (7 -3)^2 +(1 +2)^2 = r^2 = 16 +9 = 25

So, the circle's equation is ...

  (x -3)^2 +(y +2)^2 = 25 . . . . . matches choice C

__

5) As in the previous problem, the standard form equation is ...

  (x -4)^2 +(y -8)^2 = (-1-4)^2 +(7-8)^2 = 25+1 = 26

To put this in general form, we need to subtract 26 and eliminate parentheses.

  x^2 -8x +16 +y^2 -16y +64 -26 = 0

  x^2 +y^2 -8x -16y +54 = 0

__

6) A circle tangent to the y-axis will have a radius equal to the x-value of the center point.

  (x -5)^2 +(y -6)^2 = 5^2

  x^2 -10x +25 +y^2 -12y +36 = 25

  x^2 +y^2 -10x -12y +36 = 0

8 0
3 years ago
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