All categories

3 years ago

Use diagram to answer 3(x+6)=30

Mathematics

2 answers:

Alja [10]3 years ago

6 0

The answer is 4
Plug in method

3 (4)+6 =30 plug in value for x
3(4)+3(6) =30 distributive prop.
12+18=30 equals 30

Katyanochek1 [597]3 years ago

5 0

Answer:

Step-by-step explanation:

3x + 18 = 30

3x + 18 -18 = 30 - 18

3x = 12

x = 4

You might be interested in

1.your aswer:

lutik1710 [3]

Answer:

Tess is correct

Step-by-step explanation:

First off, to find out the new discounted price without the sales tax, you multiply $24.50 by 15% (0.15). This gives you $3.68. You then subtract the $3.68 from $24.50. You get $20.82. To find the total with sales tax you then multiply the $20.82 by 10% (0.1). You add the discounted price with the sales tax and get the conclusion that they have enough money for the book.

3 0

3 years ago

Read 2 more answers

Simplify: √8x^5+ x√18x^3 ÷x^2√50x

Sergeu [11.5K]

Answer:

10x^2 √2x

Step-by-step explanation:

hope this helps

lmk if it's wrong

7 0

2 years ago

The letters in the word 'PROBABILITY' were cut up and placed into a bag .A letter will be randomly selected from the bag. Whatis

Travka [436]

ugdghhfsdfg vhhzdhuijjcdfghvvv hincha

4 0

2 years ago

Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe

ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for $n\geq 78$

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: $\sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4$

For n=1: $\sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4$

From this point we will assume that $n\geq 2$

As we can see, $\sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4$ and $(4n)^4=256n^4$ . Then,

$\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4$

Now, we will use the formula for the sum of the first 4th powers:

$\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}$

Therefore:

$\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0$

and, because $n \geq 0$ ,

$465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1$