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ElenaW [278]
3 years ago
13

Question 1: Imagine that we are measuring rain fall with a rain gauge. It is raining

Mathematics
1 answer:
sdas [7]3 years ago
7 0

Answer:

13.5 inches

Step-by-step explanation:

after 5 hours = 6 inches

11 - 5 = 6 hours to go

1.25 x 6 = 7.5 inches

7.5 + 6 = 13.5 inches

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1. You buy a new car today for R120 000 and obtain finance for 80% of the purchase price over four
Yuki888 [10]
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4 0
2 years ago
Suppose that a certain movie earns $3,000,000 in ticket sales. If 60% goes to the movie and 40% goes to theatres: Movie studios
miskamm [114]

Answer: See explanation

Step-by-step explanation:

Amount earned by movie = $3,000,000.

Percentage that went to movie = 60%

Percentage that went to theater = 40%

Revenue gotten by movie studio = 60% × $3,000,000

= 0.6 × $3,000,000

= $1,800,000

Revenue gotten by theaters = 40% × $3,000,000

= 0.4 × $3,000,000

= $1,200,000

5 0
3 years ago
5 9/16<br> As an Improper fraction
evablogger [386]

Answer:

89/16

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?
Rufina [12.5K]
x is in quadrant I, so 0, which means 0, so \dfrac x2 belongs to the same quadrant.

Now,

\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}

Since \sin x=\dfrac5{13}, it follows that

\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}

Since x belongs to the first quadrant, you take the positive root (\cos x>0 for x in quadrant I). Then

\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}

\tan x is also positive for x in quadrant I, so you take the positive root again. You're left with

\tan\dfrac x2=\dfrac15
4 0
3 years ago
Round 2.372 to the nearest tenth
creativ13 [48]
There is no ones place after the decimal so 3 is in the tenth place, so 2.4
8 0
3 years ago
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