Answer:
y = -7x + 57
Step-by-step explanation:
If the line is parallel, it will have the same slope. So, this line will also have a slope of -7.
Use y = mx + b, plug in the slope and given point, and solve for b:
y = mx + b
-6 = -7(9) + b
-6 = -63 + b
57 = b
Plug in the slope and y intercept into y = mx + b:
y = mx + b
y = -7x + 57
So, the equation is y = -7x + 57
Let us assume the regular price of each tube of paint = r.
0.50 off each tube.
New price of each tube = r - 0.50.
She buy 6 tubes.
Total price of 6 tubes = 6×(r-0.50).
We are given total price = $84.30 .
Therefore, we can setup an equation
6×(r-0.50) = 84.30.
Distributing 6 over (r-0.50), we get
6r - 3.0 = 84.30
Adding 3.0 on both sides, we get
6r - 3.0+3.0 = 84.30+3.0
6r = 87.30
Dividing both sides by 6, we get
6r/6 = 87.30/6
r = 14.55
<h3>Therefore, required equation is
6(r-0.50) = 84.30 and the regular price of each tube of paint is $14.55.</h3>
Answer:
y = 4x + 6
Step-by-step explanation:
Turn the equation we are given into slope-intercept form.
y - 5 = -1/4(x + 8)
y - 5 = -1/4x - 2
y = -1/4x + 3
The slope of a perpendicular line is the opposite reciprocal of the original line.
-1/4 -> 4/1 -> 4
Find the new y-intercept using the point given.
y = 4x + b
2 = 4(-1) + b
2 = -4 + b
6 = b
Fill in everything we solved for.
y = 4x + 6
Best of Luck!
Answer:
-4/8
Step-by-step explanation:
that's what my math says
<h3>There are two answers: Choice C, Choice D</h3>
Explanation:
For any acute triangle, the center of the circle is always inside the triangle.
For any right triangle, the center of the circle is the midpoint of the hypotenuse. The hypotenuse is the diameter of the circle.
For any obtuse triangle, the center of the circle is outside the triangle.
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Let's look at the answer choices more closely
A. False. This is only true if we have a right triangle as mentioned earlier.
B. False. This describes an inscribed circle.
C. True. As stated earlier.
D. True. This is based on how the circumscribed triangle is defined. It is set up to be the circle that goes through all three vertex points of a triangle. In other words, it is the smallest circle to completely enclose the given triangle.
