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tatiyna
3 years ago
8

Please help as soon as possible 50 points

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
8 0

Answer:

the answer is d. 4x²+x-6

Step-by-step explanation:

In order to combine the fractions, they need to have the same denominator.

So, multiply each of their numerators by the denominator they need to be equivalent.

This would look like this:

3x/x+3 --> 3x(x)/x(x+3)        ---simplify this as--> 3x²/x(x+3)

x-2/x  --> (x-2)(x+3)/x(x+3)  ---simplify this as --> x²+x - 6/x(x+3)

3x                    3x(x)                                     x-2                   (x-2)(x+3)

-----      --->        -----                 and             --------   --->           ---------

x+3                   x(x+3)                                    x                        x(x+3)

now that both fractions have the same denominator, we can add their numerators.

3x² + x²+x-6 = 4x²+x -6

This should now look like this:

4x²+x -6

-------------

x(x+3)

Nadusha1986 [10]3 years ago
3 0

ANSWER:

On solving expression, we get

\longrightarrow\sf\frac{3x}{x + 3}  +  \frac{x - 2}{x}

\longrightarrow\sf\frac{{3x}^{2} + {x}^{2}  - 2x + 3x - 6  }{(x + 3)x}

\longrightarrow\sf\frac{{4x}^{2}  + x - 6}{ x(x + 3)}

So, <u>Correct choice</u> - [D]

\large\boxed{\sf\frac{{4x}^{2}  + x - 6}{ x(x + 3)}.}

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In triangle RST, m∠R &gt; m∠S + m∠T. Which must be true of triangle RST? Check all that apply.
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Answer:

1. m∠R > 90°

2. m∠S + m∠T < 90°

4. m∠R > m∠T

5. m∠R > m∠S

Step-by-step explanation:

<h3>General strategy</h3>
  1. prove the statement starting from known facts, or
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Helpful fact:  Recall that the Triangle Sum Theorem states that m∠R + m∠S + m∠T = 180°.

<u>Option 1.  m∠R > 90°</u>

Start with m∠R > m∠S + m∠T.

Adding m∠R to both sides of the inequality...

m∠R + m∠R > m∠R + m∠S + m∠T

There are two things to note here:

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2* m∠R > 180°

Dividing both sides of the inequality by 2...

m∠R > 90°

So, the first option must be true.

<u>Option 2.  m∠S + m∠T < 90°</u>

Start with m∠R > m∠S + m∠T.

Adding (m∠S + m∠T) to both sides of the inequality...

m∠R + (m∠S + m∠T) >  m∠S + m∠T + (m∠S + m∠T)

There are two things to note here:

  1. The left side of this inequality is exactly equal to the Triangle Sum Theorem expression
  2. The right side of the inequality is 2*(m∠S+m∠T)

Substituting

180° > 2* (m∠S+m∠T)

Dividing both sides of the inequality by 2...

90° > m∠S+m∠T

So, the second option must be true.

<u>Option 3.  m∠S = m∠T</u>

Not necessarily.  While m∠S could equal m∠T, it doesn't have to.  

Example 1:  m∠S = m∠T = 10°;  By the triangle sum Theorem, m∠R = 160°, and the angles satisfy the original inequality.

Example 2:  m∠S = 15°, and m∠T = 10°;  By the triangle sum Theorem, m∠R = 155°, and the angles still satisfy the original inequality.

So, option 3 does NOT have to be true.

<u>Option 4.  m∠R > m∠T</u>

Start with the fact that ∠S is an angle of a triangle, so m∠S cannot be zero or negative, and thus m∠S > 0.

Add m∠T to both sides.

(m∠S) + m∠T > (0) + m∠T

m∠S + m∠T > m∠T

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠T.

So, option 4 must be true.

<u>Option 5.  m∠R > m∠S</u>

Start with the fact that ∠T is an angle of a triangle, so m∠T cannot be zero or negative, and thus m∠T > 0.

Add m∠S to both sides.

m∠S + (m∠T) > m∠S + (0)

m∠S + m∠T > m∠S

Recall that m∠R > m∠S + m∠T.

By the transitive property of inequalities, m∠R > m∠S.

So, option 5 must be true.

<u>Option 6.  m∠S > m∠T</u>

Not necessarily.  While m∠S could be greater than m∠T, it doesn't have to be.  (See examples 1 and 2 from option 3.)

So, option 6 does NOT have to be true.

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