Mrs. Alberts has two seventh grade math classes this year. They took their final exam, and Mrs. Alberts just finished grading th
em. She made a box-and-whisker plot for each class in order to compare their results.
Analyze the box-and-whisker plots from above and then select the following comparative inferences that are true. Select all that apply.
1. The interquartile range of Class A is about twice as large as the interquartile range of Class B.
2. There is very little overlap in the two data sets.
3. The median of Class A is about 5 points higher than the median of Class B.
4. The range of Class B is about 12 points less than the range of Class A.
5. A student in Class B had the highest score of both classes.
6. In general, the students from Class B scored better than the students from Class A.
Analyze the box-and-whisker plots from above and then select the following comparative inferences that are true. Select all that apply.
1. The interquartile range of Class A is about twice as large as the interquartile range of Class B.
2. There is very little overlap in the two data sets.
3. The median of Class A is about 5 points higher than the median of Class B.
4. The range of Class B is about 12 points less than the range of Class A.
5. A student in Class B had the highest score of both classes.
6. In general, the students from Class B scored better than the students from Class A.
1 answer:
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Answer:
<em>Option C</em>
Step-by-step explanation:
Consider each of these graphs. Let us formulate an inequality for each of them, and match the one with an inequality of ;
Graph 3 is the only one that matches with the inequality provided to us.
* Note that shaded circles are represented by a greater / less than or equal to, and non - shaded circles are represented by a greater / less than sign.
<em>Solution ⇒ Graph 3</em>
Answer:
See explanation
Step-by-step explanation:
You are given the equation
1. Add 8 negative x-tiles to both sides of the equation to create a zero pair on the left side. The equation then will have form
2. Add 5 negative unit tiles to both sides of the equation to create a zero pair on the right side. The equation now is
3. Divide both sides by 3: