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3 years ago

Find the missing measure in the triangle below.

Mathematics

2 answers:

denis23 [38]3 years ago

7 0

Answer:

Step-by-step explanation:

To find x take 180 and subtract 63 and 77

mariarad [96]3 years ago

6 0

Answer:

40 degrees

Step-by-step explanation:

All measures in an angle add up to 180 degrees. So since here you have the measures 63 and 77, you would add both of those up and subtract that from 180, and the remainder would be your answer.

So,

63 + 77 = 140

180 - 140 = 40 degrees

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Answer:

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Step-by-step explanation:

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3 years ago

The two triangles are similar to each other. How long is the side labeled “?”

Mandarinka [93]

Answer:

Step-by-step explanation:

The smaller triangle seems to have dilated and formed the larger triangle. So, let's find the factor of increase.

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Hope that helps!

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3 years ago

A group of 6p people are renting a vacation house together the price of the rental is 3p to the 2nd power if they split the cost

Tanya [424]

So we just do
cost/number of people=cost per 1 person
so
(6p)/(3p^2)
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easy way is
remember that
(x^m)/(x^n)=x^(m-n)
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3 years ago

The graph of a sinusoidal function has a minimum point at (0,3)(0,3) and then intersects its midline at (5π,5)

bekas [8.4K]

Answer: F(x) = 2*sin(x/10 +(3/2)*pi) + 5

Step-by-step explanation:

The information that we have is that:

We have a minimum at (0, 3)

the midline is at (5*pi, 5)

This is a sinusoidal function, so we can write one generic one as:

F(x) = A*sin(c*x + p) + B.

where A and B are constants, c is the frequency and p is a phase

First, the minimum of the sine function is when sin(x) = -1, and this happens at (3/2)*pi

We know that this minimum is at x = 0.

sin(c*0 + p) = -1

Then p = 3/2*pi.

So our function is:

F(x) = A*sin(c*x +(3/2)*pi) + B.

Now, we know that F(0) = 3, so:

3 = A*sin(c*0 +(3/2)*pi) + B = -A + B.

now we can use the other hint, the midpoint of the sine function is when sin(x) = 0, and this happens at x = 0 and x = pi, particularlly as we here have a phase of 3/2*pi, we should find x = 2*pi.

then:

c*5*pi + (3/2)*pi = 2*pi

c*5 + 3/2 = 2

c*5 = 2 - 3/2 = 1/2

C = 1/2*5 = 1/10

So our function is

F(x) = A*sin(x/10 +(3/2)*pi) + B

and we know that when x = 5*pi, F(5*pi) = 5, so:

5 = F(x) = A*sin(5*pi/10 +(3/2)*pi) + B

5 = B

and we aready knew that:

- A + B = 3

-A + 5 = 3

A = 5 - 3 = 2

So our equation is:

F(x) = 2*sin(x/10 +(3/2)*pi) + 5

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3 years ago