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3 years ago

Graph the first six terms of a sequence where a1 = 2 and r = 4.

2 answers:

8 0

We are given with
a1 = 2
r = 4

These are components of a geometric series. The first term is 2 and the common ratio is 4. To get the first six terms, we use the formula:
an = a1 r^(n-1)
a1 = 2 (4)^(1-1) = 2
a2 = 2 (4)^(2-1) = 8
a3 = 2 (4)^(3-1) = 32
a4 = 2 (4)^(4-1) = 128
a5 = 2 (4)^(5-1) = 512
a6 = 2 (4)^(6-1) = 2048

allochka39001 [22]3 years ago

6 0

The verified answer is C.

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Read 2 more answers

An open-top box with a square base is to have a volume of 4 cubic feet. Find the dimensions of the box (in ft) that can be made

Lemur [1.5K]

Answer:

The dimension of box= $2ft\times 2ft\times 1ft$

Step-by-step explanation:

We are given that

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Let x be the side of square base and h be the height of box

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Now, surface area of box,A= $x^2+4xh$

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$\frac{dA}{dx}=2x-\frac{16}{x^2}$

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$2x-\frac{16}{x^2}=0$

$2x=\frac{16}{x^2}$

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$x=2$

$\frac{d^2A}{dx^2}=2+\frac{32}{x^3}$

Substitute x=2

$\frac{d^2A}{dx^2}=2+\frac{32}{2^3}=2+4=6>0$

Hence, the area of box is minimum at x=2

Therefore, side of square base,x=2 ft

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Answer:

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