H=-16t² +v(0)t+h(0)
v(0)=192
h=-16t² +192t+h(0)
h(0) should be 0, because the mortar sits on the ground.
h= - 16t²+192t
This function will have maximum because it has minus before x², and parabola is looking down.
h=-(16t²-192t)=-(16t² -2*4t*24+24²)+24²
h=-(4t-24)²+24²
h=-(4t-24)²+576
vertex (24 feet, 576 feet)
24 feet horizontally from the mortar and 576 feet up
Answer is 3
You do rise over run
The relation is a function
A. They are symmetric about y=x
