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Lerok [7]
2 years ago
13

PLEASE SOMEONE HELP ME

Mathematics
1 answer:
evablogger [386]2 years ago
8 0

Answer:

What grade is this question?

Step-by-step explanation:

in a momment im in class

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(c) The total number of one centimeter lines in the first n diagrams is given by the expression
trapecia [35]

Answer:

I) f + g = 10/3

II) 4f + 2g = 20/3

III) f = 2 and g = 4/3

Step-by-step explanation:

From the chart,

P = 25

q = 40

The total number of one centimeter lines in the first n diagrams is given by the expression 

2/3n^3 + fn^2 + gn. 

When n = 1, the total number of line = 4. So,

2/3(1)^3 + f(1)^2 + g(1) = 4

2/3 + f + g = 4

Make f+g the subject of formula

f + g = 4 - 2/3

f + g = (12 - 2)/3

f + g = 10/3 ......(1)

When n = 2

Total number of line = 12

2/3(2)^3 + f(2)^2 + g(2) = 12

2/3×8 + 4f + 2g = 12

16/3 + 4f + 2g = 12

4f + 2g = 12 - 16/3

4f + 2g = (36 - 16)/3

4f + 2g = 20/3 ......(2)

(iii) To find the values of f and g, solve equation 1 and 2 simultaneously

f + g = 10/3 × 2

4f + 2g = 32/3

2f + 2g = 20/3

4f + 2g = 32/3

- 2f = - 12/3

f = 12/6

f = 2

Substitutes f in equation 1

f + g = 10/3

2 + g = 10/3

g = 10/3 - 2

g = (10 - 6)/3

g = 4/3

4 0
3 years ago
Shakira went bowling with her friends. She paid $3 to rent shoes and then $4.75 for each game of bowling. If she spent a total o
DaniilM [7]
They played 9.17 games
6 0
2 years ago
Read 2 more answers
the average temperature for febuary was -4.03 in chicago and -7.14 in michigan.which of the following represent the difference b
ozzi

To put it simply, the answer is 3.11.

6 0
3 years ago
Which sequence of transformations will change figure PQRS to figure P′Q′R′S′?
masya89 [10]

Answer:

Counterclockwise rotation about the origin by 90 degrees followed by reflection about the y-axis .

Step-by-step explanation:

The shape is moved to the opposite quadrant of the second shape then flied directly onto the second shape.

3 0
2 years ago
Read 2 more answers
Can someone PLEASE help me with Trigonometry???
Svetach [21]
\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\
-------------------------------\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}
\\\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)
\\\\\\
\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}

but anyway, the numerator will give the angles, and θ is just half of each

\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\
-------------------------------\\\\
sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}
\\\\\\
sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o
\\\\\\
\theta=\cfrac{-8.05}{2}\implies \theta=-4.025

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there
7 0
3 years ago
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