Answer:
The correct answer will be- 200
Explanation:
The cell cycle in eukaryotes mostly takes place in four phases: G₁, S, G₂ and M phase in sequence.
The DNA replication takes place during S phase which doubles the amount of DNA in a cell after which during M- phase the DNA divides into the daughter cell.
The amount of DNA present during G₂ phase is the 200 pg which will remain same until anaphase I as the segregation of chromosomes to the daughter cells takes place in the anaphase. Therefore, the amount of DNA observed after G₂ phase will remain 200 pg till metaphase I.
Thus, 200 is the correct answer.
<span>C. The transferred electron from lithium to fluorine provides each atom with a full outer energy level.</span>
A ruler will not be needed due to having a graduated cylinder which can help measure the volume of liquids
Answer:
B) Coating of microbe to aid phagocyte recognition
Explanation:
Opsonization is the process and mechanism which targets the foreign body and helps in the recognition of the pathogen by the phagocytic cells such as the macrophages and dendritic cell.
The opsonization enhances the process of phagocytosis as the opsonin substances which could be the antibodies, proteins or other molecules which could be easily recognised by the phagocytic cells gets attached to the pathogen.
Thus, Option-B is the correct answer.
Opsonization is the coating of a particle with proteins that facilitate phagocytosis of the particle by tissue macrophages and activated follicular dendritic cells (FDCs) as well as binding by receptors on peripheral blood cells
