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3 years ago

6

What are the x and y intercepts for -2x+y=-2

1 answer:

SpyIntel [72]3 years ago

8 0

Answer: The y intercepts would be: ( 0 , -2 ).

The x intercepts would be: ( 1 , 0 ).

Step-by-step explanation:

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3 years ago

Help me solve it please

snow_tiger [21]

Answer:

$\fbox{\begin{minipage}{5.8 em}x =5.97 cm\end{minipage}}$

Step-by-step explanation:

(1) As definition, the area ( $A$ ) of a circle is calculated by:

$A = \pi$ x $r^{2}$ with $r$ is radius of circle.

(2) The relation between radius ( $r$ ) and diameter ( $d_{1}$ ) of a circle is:

$d_{1}$ = 2 x $r$

(3) Applying the Pythagorean theorem for a square with sides of length $x$ ,

the relation between side $x$ and diagonal $d_{2}$ is:

$x^{2} +x^{2} = d^{2} \\or\\2x^{2} = d^{2}$

=> The diagonal ( $d_{2}$ ) of that square is calculated by:

$d_{2}$ = $x\sqrt{2}$

(4) The square fits exactly inside a circle, with each of its vertices being on the circumference of the circle.

Applying the theorem of inscribed angle in a circle, the measure of arc BD is twice as the measure of inscribed angle BAD.

In other words, the measure of arc AC = 2 x 90 = 180 deg, or half of circle.

It means that the diagonal BD is coincide with a diameter of circle.

=> $d_{1} = d_{2}$

or $2$ x $r$ = $x\sqrt{2}$

or $r$ = $x\frac{\sqrt{2} }{2}$

Substitute $r$ back into original formula used for calculating the area of circle:

=> A = $\pi$ x $(x\frac{\sqrt{2}}{2})^{2}$ = $\pi$ x $\frac{x^{2}}{2}$

=> $x^{2} = A$ x $\frac{2}{\pi }$

=> $x = \sqrt{A}$ x $\sqrt{\frac{2}{\pi } }$ = $\sqrt{56}$ x $\sqrt{\frac{2}{\pi } }$ = 5.97 cm

Hope this helps!

:)

4 0

3 years ago

Question 4 Multiple Choice Worth 4 points)

belka [17]

Answer:

y = 1/2x+11

Step-by-step explanation:

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3 years ago

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3 years ago

Find a point-slope form for the line with slope 1/5 and passing through the point (-2,- 7).

snow_tiger [21]

Answer:

point slope form is y-y1 = m(x-x1) which is y+7= 1/5(x + 2)

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3 years ago