Step-by-step explanation:
20 1/2 = (20×2 + 1)/2 = 41/2.
to create 1/6 of that we have to multiply it by 1/6 :
41/2 × 1/6 = 41/12 = 3 5/12
the rock weighed 3 5/12 lb.
Answer:
J'(2,-3), K'(4, -3) and L'(5,-2)
Step-by-step explanation:
The given triangle has vertices at J(2,3), K(4, 3) and L(5,2).
The transformation rule for a reflection in the x-axis is:
We substitute the points to obtain the coordinates of the image triangle J'K'L'
In other words, we negate the y-coordinates of triangle JKL to obtain the coordinates of J'K'L'
See attachment for graph.
N would equal 28 since 60-32 is 28
Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
-4 would be the correct answer to the problem
