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worty [1.4K]
2 years ago
8

Tanya has 442 pennies. If she gives away 128 of the pennies equally to 4​ friends, about how many pennies will Tanya give each​

friend? How many pennies will Tanya have​ left?
Mathematics
2 answers:
butalik [34]2 years ago
7 0

Answer:

32 pennies to each friend and 314 pennies remaining

Step-by-step explanation:

For the first step, we need to divide 128 by 4 to get the amount of pennies she gave to each friend: 128/4 = 32

For the second step, we need to subtract 128 from 442 to find out how many pennies she has left: 442-128 = 314

Hope this helps!

Usimov [2.4K]2 years ago
3 0
I think the answer is D
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3) You owe $1,842.66 on a credit card at a 14.5% APR. You pay $250.00 at the beginning of the month and put another $250.00 in a
Wittaler [7]

3. Credit Card: (1842.66 - 250) (.145/12) = $19.24

Savings: 250(0.04/12) = $0.83  

Difference = 19.24 - 0.83 = $18.41  

4. Credit Card: (1842.66 - 500) (.145/12) = $16.22

You will save $18.41 - $16.22 = $2.19 by putting all $500 toward the higher credit card rate.  

8 0
3 years ago
Read 2 more answers
Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x
iren [92.7K]

Answer:

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

Step-by-step explanation:

One is asked to find the root of the following equation:

2x^2+1=5x

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

ax^2+bx+c=0

Change the given equation using inverse operations,

2x^2+1=5x

2x^2-5x+1=0

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

Simplify,

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

\frac{5(+-)\sqrt{25-8}}{4}

\frac{5(+-)\sqrt{17}}{4}

Rewrite,

\frac{5(+-)\sqrt{17}}{4}

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

8 0
3 years ago
Construct 3 linear equation starting with qiven solution z = 1/3
Andreyy89

Answer:

(a)9z+2=5

(b)21z-11=-4

(c)4z=2-2z

Step-by-step explanation:

We are required to construct 3 linear equations starting with the given solution z = 1/3.

<u>Equation 1</u>

<u />z=\frac{1}{3}<u />

Multiply both sides by 9

9z=\frac{1}{3}\times 9\\9z=3

Rewrite 3 as 5-2

9z=5-2

Add 2 to both sides

Our first equation is: 9z+2=5

<u>Equation 2</u>

<u />z=\frac{1}{3}<u />

Multiply both sides by 21

21z=\frac{1}{3}\times 21\\21z=7

Rewrite 7 as 11-4

21z=11-4

Subtract 11 from both sides

Our second equation is: 21z-11=-4

<u>Equation 3</u>

<u />z=\frac{1}{3}<u />

Multiply both sides by 6

6z=\frac{1}{3}\times 6\\6z=2

Rewrite 6z as 4z+2z

4z+2z=2

Subtract 2z from both sides

Our third equation is: 4z=2-2z

4 0
3 years ago
3. A quadratic polynomial whose<br>product and the sum of<br>zéroes are -12 and 1​
muminat

Answer:

the equation is : x²-x-12

Step-by-step explanation:

the quadratic equation is in the form of : y=ax²+bx+c

the product of the zeros is -12 and the sum is 1

b  = - 1

c=-12 (product)

y=x²-x-12

check : factorize first (x+3)(x-4)=0

either x+3=0 then x=-3

or x-4=0 then x=4

-3*4=-12

-3+4=1

the equation is : x²-x-12

3 0
3 years ago
Need help ASAP <br>Which number line correctly shows -3 - -1.5?​
Alexandra [31]

Answer:

The top one I'm pretty sure.

3 0
2 years ago
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