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3 years ago

PLZZZ HELPPPP Assume line q is parallel to line m. Choose from the drop-down menus to solve for m∠6

Mathematics

1 answer:

Vikentia [17]3 years ago

8 0

Answer:

1= 75 2= 60 3=180 4=45 5= vertical angles 6=45

Step-by-step explanation:

All we have to do is use supplimentary angles

For example angle 1

105+angle 1=180

angle one = 75 degrees

120+angle 2=180

angle two= 60 degrees

There 180 degreees in a triagle.

So angle 1 + angle 2+ angle 7= 180

75+60+angle 7=180

angle 7= 45 degrees

And since 6 and 7 are vertical angles, angle 6 is also 45 degrees.

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The coordinates of rectangle ABCD are A(1, 2), B(4, 5),C(9, 0) and D(6, -3). What is the area of the rectangle? 18 square units

Natali5045456 [20]

In order to find the area of a rectangle, the formula is L*W (Length multiplied by Width). Our goal is to find these two measurements, so we will take the following steps:
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3 years ago

Solve the inequality

GenaCL600 [577]

-1 < c + 2 < 3....subtract 2 from all sections
-1 - 2 < c + 2 - 2 < 3 - 2...simplify
-3 < c < 1
==============================
32 > 16 - 4g > 12....subtract 16 from all sections
32 - 16 > 16 - 16 - 4g > 12 - 16....simplify
16 > -4g > -4 ...now divide all sections by -4, and change inequality signs
16/-4 < (-4/-4)g < -4/-4...simplify
-4 < g < 1
============================
6y + 1 > = 10
6y > = 10 - 1
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-3/2y > = 9 ....multiply both sides by -2/3, cancelling the -3/2 on the left...and change the inequality sign
y < = 9 * -2/3
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3 years ago

1. In an auditorium, there are 21 seats in the first row and 26 seats in the second row. The number of seats in a row continues

kondor19780726 [428]

1. Let $s_n$ be the number of seats in the $n$ -th row. The number seats in the $n$ -th row relative to the number of seats in the $(n-1)$ -th row is given by the recursive rule

$s_n=s_{n-1}+5$

Since $s_1=21$ , we have

$s_2=s_1+5$
$s_3=s_2+5=s_1+2\cdot5$
$s_4=s_3+5=s_1+3\cdot5$
$\cdots$
$s_n=s_{n-1}+5=\cdots=s_1+(n-1)\cdot5$

So the explicit rule for the sequence $s_n$ is

$s_n=21+5(n-1)\implies s_n=5n+16$

In the 15th row, the number of seats is

$s_{15}=5(15)+16=91$

2. Let $p_n$ be the amount of profit in the $n$ -th year. If the profits increase by 6% each year, we would have

$p_2=p_1+0.06p_1=1.06p_1$
$p_3=1.06p_2=1.06^2p_1$
$p_4=1.06p_3=1.06^3p_1$
$\cdots$
$p_n=1.06p_{n-1}=\cdots=1.06^{n-1}p_1$

with $p_1=40,000$ .

The second part of the question is somewhat vague - are we supposed to find the profits in the 20th year alone? the total profits in the first 20 years? I'll assume the first case, in which we would have a profit of

$p_{20}=1.06^{19}\cdot40,000\approx121,024$

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$p_n=4p_{n-1}$

starting with $p_1=3$ .

We can apply the same reason as in (2) to find the explicit rule for the sequence, which you'd find to be

$p_n=4^{n-1}p_1\implies p_n=4^{n-1}\cdot3$

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Step-by-step explanation:

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PLZZZ HELPPPP Assume line q is parallel to line m. Choose from the drop-down menus to solve for m∠6​​

PLZZZ HELPPPP Assume line q is parallel to line m. Choose from the drop-down menus to solve for m∠6