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elixir [45]
3 years ago
6

In a real pully system the work supplied must be _____ the work accomplished​

Physics
2 answers:
Hunter-Best [27]3 years ago
4 0

Answer:

hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

Explanation:

nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn

Lilit [14]3 years ago
3 0
I think it’s friction
Hope that helped XD
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Human industrialization, because without greenhouse gases the planet would be less warm

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A 60 watt light bulb runs for 5 seconds. How much energy does<br> it use?
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41. Electric and magnetic forces can both make certain objects move. For example, a positively charged particle will repel anoth
notsponge [240]

Answer:

Place the north pole of a magnet next to the north pole of another magnet.

Explanation:

Looking at the comments, we can see that the options are:

Place the south pole of a magnet next to the north pole of another magnet.

Place the north pole of a magnet next to the north pole of another magnet.

First, we know that a positively charged particle will repel another positively charged particle.

The same thing happens for magnetic forces (usually we define a magnetic flow from the south pole to the north pole, so we can define the south pole as the "positive" and the north pole as the "negative", but this is only notation and do not really matter), a south pole of a magnet will repel another south pole of a magnet (and the same happens for the north poles)

Then the correct option is:

Place the north pole of a magnet next to the north pole of another magnet.

8 0
3 years ago
Suppose the voltage source for a series RL-circuit were given as V0sin(ωt) instead of V0cos(ωt). Write an expression for the cur
Gala2k [10]

Answer:

Explanation:

This is an RL circuit, therefore:

Impedance; z = \mathbf{\sqrt{R^2+L^2}}

\mathbf{z = \sqrt{R^2+(Lw)^2}}

Current amplitude

\mathbf{I_o = \dfrac{V_o}{z}} \\ \\  \mathbf{I_o = \dfrac{V_o}{\sqrt{R^2+L^2\omega ^2}}}

a)

Given that:

V_o = 1.9 \ V \\ \\ \omega= 51 \ rad/s\\\\ R = 21 \Omega \\ \\  L = 0.52 H

∴

I_o= \dfrac{1.9}{\sqrt{21^2+(0.52\times 51)^2}}

\mathbf{I_o= 0.0562}  \\ \\ \mathbf{I_o = 56.2 \ mA}

b)

Phase constant :

tan  \ \phi = \dfrac{L \omega}{R } \\ \\  tan  \ \phi = \dfrac{0.52 \times 51}{21} \\ \\  tan \phi = 1.263

\text{Phase constant : }\phi = tan^{-1} (1.263)   \\ \\  \phi = 51.6^0\\ \\\text{To radians} \phi  = 51.6 \times \dfrac{\pi}{180} \\ \\  \phi = 0.287 \pi \\ \\ \mathbf{\phi = 0.9 \ rad}

3 0
3 years ago
Describe Newton's Three Laws of Motion
mart [117]

Answer:

1: an object will stay still until acted on by another force

2: acceleration of an object depends on the mass of the object and the force applied

3: for every action there is an equal and opposite reaction

8 0
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