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3 years ago

Define the relationship between force acceleration and mass

1 answer:

4 0

Force is mass times acceleration. This means an object with a larger mass needs a stronger force to be moved along at the same acceleration as an object with a small mass

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Explain in detail what specific factors affect the momentum of a bicycle going down hill.

Crazy boy [7]

Mass and velocity are the two terms which affect momentum of a bicycle going hill down.

Explanation:

As we know that Momentum describes the motion of an object. It is the combination of the objects mass and velocity.

So, obviously with no doubt mass and velocity are the two terms which affect momentum.

Momentum(p) = Mass(m) * Velocity(v)

The momentum also depends upon the mass and speed of the object.

More the mass of the object more is the momentum.

Depending upon the gravity and bicycle's motion speed momentum varies.

Bicycle moves faster the down hill if it moves with some speed as it has lesser mass the momentum also will be less.

4 0

3 years ago

Consider a cylindrical crew module with a diameter of 5 meters, a length of 15 meters, and a crew of 6 people. The module contai

UNO [17]

Answer:

294.524 m^3

Explanation:

The volume of a cylinder is given by the formula ...

V = πr^2h

For a radius of 2.5 m and a length of 15 m, the volume is ...

V = π(2.5 m)^2(15 m) = 93.75π m^3 ≈ 294.524 m^3

The volume is about 294.52 cubic meters.

7 0

3 years ago

Some planetary scientists have suggested that the planet Mars has an electric field somewhat similar to that of the earth, produ

aalyn [17]

Answer:

324795 C

252.637820565 N/C

$2.235844712\times 10^{-9}\ C/m^2$

Explanation:

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

R = Radius of Mars = $3.4\times 10^6\ m$

A = Area = $4\pi R^2$

$\phi$ = Electric flux = $3.67\times 10^{16}\ Nm^2/C$

Electric flux is given by

$\phi=\dfrac{q}{\epsilon_0}\\\Rightarrow q=\phi\epsilon_0\\\Rightarrow q=3.67\times 10^{16}\times 8.85\times 10^{-12}\\\Rightarrow q=324795\ C$

The charge is 324795 C

Electric field is given by

$E=\dfrac{\phi}{A}\\\Rightarrow E=\dfrac{3.67\times 10^{16}}{4\pi (3.4\times 10^6)^2}\\\Rightarrow E=252.637820565\ N/C$

The electric field is 252.637820565 N/C

Surface charge density is given by

$\sigma=\dfrac{q}{4\pi R^2}\\\Rightarrow \sigma=\dfrac{324795}{4\pi (3.4\times 10^6)^2}\\\Rightarrow \sigma=2.235844712\times 10^{-9}\ C/m^2$

The surface charge density is $2.235844712\times 10^{-9}\ C/m^2$

6 0

3 years ago

An archer pulls her bowstring back 0.400 m by exerting a force that increases uniformly from zero to 230 N. (a) What is the equi

tino4ka555 [31]

Answer: An archer pulls her bowstring back 0.400m by exerting a force that increases uniformly from zero to 230N. The equivalent spring constant of the bow will be 575N/m

Explanation: To find the answer, we have to know about the Simple Harmonic Motion.

<h3>What is Simple Harmonic Motion?</h3>

A particle is said to execute simple harmonic motion, if it moves to and fro about mean position under the action of restoring force.
The restoring force is directly proportional to its displacement from the mean position and always directed towards the mean position.
If x is the displacement from the mean position, and F is the restoring force, then

$F$ ∝ $-x$

$F=-kx$ where, k is called the spring constant.

<h3>How to approach the problem?</h3>

Given that, an archer pulls her bowstring back 0.400m by exerting a force that increasing from zero to 230N.
Here, from the question given, we can write, $x=-0.400m$ and $F=230N$ .
Thus, our spring constant k will be,