Jack works after school. Each day he is paid a set amount, plus an hourly wage. Look at the table.

An ANOVA procedure is used for data that were obtained from four sample groups each comprised of five observations. The degrees

jeyben [28]

Answer:

(3,16)

Step-by-step explanation:

The degrees of freedom of the critical value F are (k-1,n-k).

We are given that there are four sample group, so,

k=4.

Also, we are given that the each four groups contains five observations, so,

n=4*5

n=20

The critical value F has degree of freedom

(k-1,n-k)

(4-1,20-4)

(3,16).

Thus, the degrees of freedom for the critical value of F are (3,16).

6 0

2 years ago

What is the volume of a hemisphere that

ch4aika [34]

Given:

Given that the diameter of the hemisphere is 12.6 cm

The radius of the hemisphere is given by

$r=\frac{d}{2}=\frac{12.6}{2}=6.3$

We need to determine the volume of the hemisphere.

Volume of the hemisphere:

Let us determine the volume of the hemisphere.

The volume of the hemisphere can be determined using the formula,

$V=\frac{2}{3} \pi r^3$

Substituting the values, r = 6.3 and π = 3.14, we have;

$V=\frac{2}{3} (3.14)(6.3)^3$

Simplifying the values, we have;

$V=\frac{2}{3} (3.14)(250.047)$

$V=\frac{1570.29516}{3}$

Dividing, we have;

$V=523.43172$

Rounding off to the nearest tenth, we get;

$V=523.4$

Thus, the volume of the hemisphere is 523.5 cm³

6 0

2 years ago

A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the

Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of metal

y ----> the original width of the piece of metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

$L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in$

The volume of the box is equal to

$V=(x-10)(y-10)5$

$V=930\ in^3$

so

$930=(x-10)(y-10)5$

simplify

$186=(x-10)(y-10)$ -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

so

$x=y+25$ ----> equation B

substitute equation B in equation A

$186=(y+25-10)(y-10)$

solve for y

$186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

$x=16+25=41$

therefore

The original length was 41 inches and the original width was 16 inches

3 0

2 years ago

Given that the solution set to a system of three linear equations is a line, which of the following is true about the system?

Setler79 [48]

The correct answer is:

d) The system can only be dependent and consistent.

Explanation:

In order for the solution to a system of equations to be a line, this means that the lines must lie on top of one another. This means they are the same line; the system is consistent since there is at least one solution, and dependent since all of the points in one equation work for the other equations as well.

8 0

2 years ago

Read 2 more answers

A city wants to show that the mean number of public transportation users per day is more than 5,575. Identify the null hypothesi

jeyben [28]

Answer:

$H_0:\mu\leq 5575$