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Ksju [112]
3 years ago
8

ANSWER PLEASE *50 POINTS*

Mathematics
1 answer:
zvonat [6]3 years ago
3 0

If a football player runs 5/6 of a mile every 3/4th of a hour, that means every 1/4th a hour he runs 1.5/6th of a mile.

That means every 15 minutes the football player runs .2 of a mile. That means that every hour he runs :

0.8 of a mile!

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Can x = 0 in the equation below? Explain. 4 + x + 2 > 8
solong [7]

Answer:

No, x can't equal zero.

Step-by-step explanation:

substitute x for zero. now the equation says 4+0+2>8

4+2 is 6 so 6 < 8. 6 is less than 8 not greater, therefore x can't be zero

7 0
4 years ago
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Complete the equation of the line through (1, 4) and (2,2).<br> Use exact numbers.
Delicious77 [7]

Answer: If your asking for the slope then its -2/1

Step-by-step explanation:

8 0
3 years ago
Solve this. 6x+9=27−3x
MissTica

Answer:

x=2

Do you like BTS??

3 0
3 years ago
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A major credit card company has determined that customers charge between $100 and $1100 per month. If the monthly amount charged
Alexxx [7]

Answer:

a) E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600

b) First we need to calculate the variance given by this formula:

Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33

And the deviation would be:

Sd(X) = \sqrt{83333.33}= 288.675

c) P(600 < X< 889) = P(X

And using the cdf we got:

P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289

d) P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578

Step-by-step explanation:

For this case we define the random variable X who represent the customers charge, and the distribution for X on this case is:

X \sim Unif (a= 100,  b=1100)

Part a

For this case the average is given by the expected value and we can use the following formula:

E(X) = \frac{a+b}{2} = \frac{100+1100}{2}=600

Part b

First we need to calculate the variance given by this formula:

Var(X) = \frac{(b-a)^2}{12}= \frac{(1100-100)^2}{12} = 83333.33

And the deviation would be:

Sd(X) = \sqrt{83333.33}= 288.675

Part c

For this case we want to find the percent between 600 and 889, so we can use the cumulative distribution function given by:

F(x) = \frac{X -100}{1100-100}= \frac{x-100}{1000}, 100 \leq X \leq 1100

And we can find this probability:

P(600 < X< 889) = P(X

And using the cdf we got:

P(600 < X< 889)= F(889) -F(600) = \frac{889-100}{1000} -\frac{600-100}{1000}= 0.789- 0.5= 0.289

Part d

P(311 < X< 889) = P(X

And using the cdf we got:

P(311 < X< 889)= F(889) -F(311) = \frac{889-100}{1000} -\frac{311-100}{1000}= 0.789- 0.211= 0.578

6 0
3 years ago
The coordinate of two point P(4,6) and Q(5,-7) then find (abicissa of P) -(abicissa of Q)
grandymaker [24]

The value of (abscissa of P) -(abscissa of Q) is -1.

The given coordinates are P(4,6) and Q(5,-7).

We need to find (abscissa of P) -(abscissa of Q).

<h3>What is abscissa?</h3>

The horizontal coordinate of a point in a planar Cartesian coordinate system that is determined by measuring parallel to the x-axis is what abscissa stands for.

Now, (abscissa of P) -(abscissa of Q)=4-5=-1

Hence, the value of (abscissa of P) -(abscissa of Q) is -1.

To learn more about abscissa visit:

brainly.com/question/1214621.

#SPJ1

7 0
3 years ago
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