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Bumek [7]
2 years ago
8

Three angles are in the ratio 2 : 3 : 5 The smallest angle is 50 degrees Work out the sizes of the other two angles

Mathematics
1 answer:
kvasek [131]2 years ago
7 0

Answer:

Step-by-step explanation:

Let angles are 2x,3x,5x

So given 2x=50

X=25.

3x=3×25=75.

5x=5×25=125.

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17 is what percent of 340
AleksAgata [21]

Answer:

5%

Step-by-step explanation:

to work out what percent 17 is out of 340 we can formulate an equation

so 340(x%)=17

when we solve for x we get 5

4 0
2 years ago
Explain why you should récord a 1 in the tens columna when you regroup in addition problem
ser-zykov [4K]
You should write a 1 because I f what you add is 11, 12, 13, 14, 15, 16, 17, 18, or 19 there is a 1 in the front of the numbers so you must put a 1 but if the number was 76 the number in the front is 7 so you would put 7 on the tens column.

8 0
3 years ago
How do I find the sum of this series?<br>Question D
raketka [301]
Sum of an infinite geometric sequence with the common ratio r, and the first term a1 is \frac{a_1}{1-r}

we notice
-2 times -1/4=1/2,
1/2 times -1/4=-1/8
so a1=-2
r=-1/4 or -0.25

so the sum is
\frac{-2}{1-(-0.25)}=
\frac{-2}{1+0.25}=
\frac{-2}{1.25}=
\frac{-8}{5}=
the sum is -8/5 or -1.6
8 0
3 years ago
The graph of a quadratic function contains the points
masya89 [10]

Answer:

Shawn is correct.

Step-by-step explanation:

Let the quadratic function is g(x) = a(x - h)² + k

Here (h, k) is the vertex of the parabola.

Since this parabola passes through (0, 0), (1, 9) and (-1, 9), axis of symmetry is x = 0 and the vertex is (0, 0).

Therefore, equation of the parabola will be,

g(x) = a(x - 0)²+ 0

g(x) = ax²

for a point (1, 9) which lies on the graph,

9 = a(1)²

a = 9

g(x) = 9x² (here a > 1)

Therefore, f(x) is vertically stretched by a factor of 9 to form g(x).

Shawn is correct.

3 0
3 years ago
Can anyone help me solve this Algebra 2 Problem, i literally cant figure it out
Andrews [41]

Answer:

Zeros : 1 , -1, 3

Degree : 4

End Behaviour : At x-> ∞ f(x) -> ∞ and x->-∞ f(x) -> ∞

Y - intercept : -3

Extra Points: (0,-3), (2,-3)

Step-by-step explanation:

f(x) = 0 to find the zeros

Therefore (x+1)(x-1)^{2} (x-3) = 0

Clearly x = -1,1,3

Here 1 is a repeating root as it is (x-1)²

Degree is highest power of x in f(x)

Clearly it is x*x²*x = x⁴ is the maximum power of x

Thus degree is 4

Looking at end behavior we substitute x->∞ and x-> -∞

Clearly f(x)>0 as all terms are positive and f(x)->∞

Similarly when x->-∞

f(x)>0 as 2 terms are -ve and their product is positive thus f(x)-> ∞

Y-Intercept is f(0)

f(0) = (0+1)(0-1)²(0-3) = 1*1*-3 = -3

Thus Y-Intercept is -3

Substitute x = 0 , 2 for extra points

Thus f(0) = -3

and f(2) = -3

Thus points on the graph (0,-3), (0,2)

We can use all this information to draw a graph remember that 1 is a repeating root so that will be a point of minima. The graph is a parabola that passes through x-axis at x = -1, 3.

5 0
3 years ago
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