Name at least 6 angles coterminal to the angle 23. these angles must be in radians.

1 answer:

5 0

You should ask your parent/guardian
or teacher if needed! Merry Christmas!You should ask your parent/guardian
or teacher if needed! Merry Christmas!You should ask your parent/guardian
or teacher if needed! Merry Christmas!You should ask your parent/guardian
or teacher if needed! Merry Christmas!You should ask your parent/guardian
or teacher if needed! Merry Christmas!You should ask your parent/guardian
or teacher if needed! Merry Christmas!

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Find the value of x

gayaneshka [121]

Answer:

42°

Step-by-step explanation:

Since all the angles in the figure add up to 180°...

180 - 54 = 126

3x = 126°

x = 126 ÷ 3 = 42

4 0

2 years ago

This year the CDC reported that 30% of adults received their flu shot. Of those adults who received their flu shot,

Vlad [161]

Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

Conditional Probability

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem:

Event A: Person has the flu.

Event B: Person got the flu shot.

The percentages associated with getting the flu are:

20% of 30%(got the shot).

65% of 70%(did not get the shot).

Hence:

$P(A) = 0.2(0.3) + 0.65(0.7) = 0.515$

The probability of both having the flu and getting the shot is:

$P(A \cap B) = 0.2(0.3) = 0.06$

Hence, the conditional probability is:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.515} = 0.1165$

0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

To learn more about conditional probability, you can take a look at brainly.com/question/14398287

7 0

1 year ago

Can you please explain and answer this question to me, (don't mind the blue dots, they are the answers of what I think, please l

Fofino [41]

I started with c, but you could’ve started with any box.

So I took the numbers in the c box (the black box in my picture) and divided to see which were multiples of two. They all were.

Then I went to a. All of a’s numbers were divisible by 7.

Then b. Two of them are divisible by 2, so that’s not the answer. None of them were divisible by 7, so there’s your answer!

Then d. Two are divisible by 7, so your rules is divisible by 2.

I hope this helps!