1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
algol13
4 years ago
15

Jasmine has 5 books that she wants to read. She wants to read the nonfiction book first and the mystery book last. In how many d

ifferent orders can she read the books?
Mathematics
2 answers:
MissTica4 years ago
7 0

We have been given that Jasmine has 5 books and she wants to read the nonfiction book first and the mystery book last. It means that the time of reading of 2 books are fixed. Now she has 3 books which she needs to arrange.

Now, we know that n different things can be arranged in n! ways. We can use this concept to find the number of different orders can she read the books.

Using the above concept, 3 books can be arranged in 3! ways.

3!=1\times 2\times 3 \\
3!=6

Therefore, there are 6 different orders in which she can read the books.

umka21 [38]4 years ago
4 0
The different combinations is 9, since we can't rearrange the two novels.
I did 3*3 which equals 9.
You might be interested in
Simplify -5 1/4 - (-7 1/2) please<br> also ignore my tabs pls
Kruka [31]

Answer: 1/8

Step-by-step explanation:

1/2 x 1/4 = 1 x 1/2 x 4

8 0
3 years ago
In the problem • N = 1, N must be
Basile [38]
The answer is 1 by multiplying by itself
6 0
3 years ago
You might need:
Kruka [31]

This question is incomplete.

Complete Question

Astrid is in charge of building a new fleet of ships. Each ship requires 40 tons of wood, and accommodates 300 sailors. She receives a delivery of 4 tons of wood each day. The deliveries can continue for 100 days at most, afterwards the weather is too bad to allow them. Overall, she wants to build enough ships to accommodate at least 2100 sailors. How much wood does Astrid need to accommodate 2100 sailors?

Answer:

280 tons of wood.

Step-by-step explanation:

From the above question:

To make 1 ship = we require 40 tons of wood.

1 ship = can accommodate 300 sailors.

Step 1

If :

300 sailors = 1 ship

2100 sailors = y ships

Cross Multiply

300 × y ships = 1 ship × 2100 sailors

y ships = 2100 / 300

y ships = 7

Hence, 2100 sailors can occupy 7 ships.

Step 2

We are told in the question that:

Astrid wants to build enough ships to accommodate at least 2100 sailors. How much wood does Astrid need to accommodate 2100 sailors?

If:

1 ship = 40 tons of wood

Since 7 ships can accommodate 2100 sailors,

7 ships =

7 × 40 tons of wood = 280 tons of wood.

Therefore , Astrid needs 280 tons of wood to accommodate 2100 sailors.

6 0
3 years ago
Help! I have no idea!
qwelly [4]
I believe is C and D because

C. The original rectangle width is 2m and the length is 4m. And to make the other rectangle they are adding .5 m to both the width and length

D. The original rectangle has a width of 2m and length of 4m. To make the other rectangle they are substracting 1 m from the width and length
5 0
3 years ago
How to solve x(x-3)=0
damaskus [11]

Step-by-step explanation:

x(x-3)=0

x=0 or (x-3) =0

x= 0 or x =3

7 0
3 years ago
Other questions:
  • Which one of the following proportions is true for the segments shown in the figure if lines a, b, and c are parallel to each ot
    12·1 answer
  • What are the solutions of x2 -7x+13 = 0 ?
    8·1 answer
  • Is this correct ???? please help
    12·1 answer
  • 1. Which inequality matches the graph?
    7·1 answer
  • Where do y=10x+20 and y=5x+50 intercept
    12·1 answer
  • Cindy went to a candy store today. She was looking to get a whole bunch of candy. Her two favorite candies are chocolate bars an
    9·1 answer
  • Find the value of X <br> 7/x-10 = 3/6
    15·2 answers
  • X = 42 whats the answer
    7·1 answer
  • Please help !! <br><br> What is the general equation to the √x?
    14·1 answer
  • Please help asap or give explanation for brainliest
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!