Answer:
a. P= 0.6364
b. P = 0.3636
c. Q = $21.25
d. P = 0.5
Step-by-step explanation:
given data
value of a stock varies = $13 to $24
solution
P (stock value is more than $17)
P = 
P = 
P = 0.6364
and
P (value of the stock is between $17 and $21)
P = 
P = 
P = 0.3636
and
Let the upper quartile be Q


(24 - Q) = 2.75
so
Q = $21.25
and
P(X > 20 | X > 16)
P = 
P = 
P = 0.5
Umm what is this supposed to mean more information
Answer:
= 3.134 × 10^9
(scientific notation)
= 3.134e9
(scientific e notation)
= 3.134 × 10^9
(engineering notation)
(billion; prefix giga- (G))
= 3134000000
(real number)
Step-by-step explanation:
Answer: 0.7748
Step-by-step explanation:
Given : Number of bit bulls at the pound = 18
Number of pit bulls have attacked another dog in the last year =4
The proportion of pit bulls have attacked another dog in the last year:
Number of the pit bulls selected = 6
The probability of that none of the pit bulls in Joe's group attacked another dog last year : 
By using binomial , the probability that at least one of the pit bulls in Joe's group attacked another dog last year is given by :-

Hence, the required probability = 0.7748