A line that is tangent to each of the two coplanar circles
The speed of the ball is
ds/dt = 32t
At t =1/2 s
ds/dt = 16 ft/s
The distance from the ground
50 - 16(1/2)^2 = 46 ft
The triangles formed are similar
50/46 = (30 + x)/x
x = 345 ft
50 / (50 - s) = (30 + x)/x
Taking the derivative and substituing
ds/dt = 16
and
Solve for dx/dt
Answer:
Length = 15 cm, width = 12 cm, Perimeter = 54 cm
Step-by-step explanation:
The ratio of the length and breadth of a rectangle is 5:4 and its area is 180 cm².
Length = 5x
Breadth = 4x
Area of rectagle,
A = bl
180 = 5x × 4x
180 = 20x²
x² = 9
x = 3
Length = 5x = 5(3) = 15 cm
Width = 4x = 4(3) = 12 cm
Perimeter of rectangel,
P = 2(l+b)
= 2(15+12)
= 54 cm
Hence, this is the required solution.
Answer:
1. 125
2. 25
3. 40
4. 39
First question:
(15-10)^2 + (15-5)^2
parentheses first to get 5^2 + (15-5)^2
exponents next to get 25 + (15-5)^2
parentheses again 25 + 10^2
exponents again 25 + 100 = 125
Second question:
simplify the exponents (3 *3) + (4 * 4) + (2 * 2) to get 9 + 16 + 4 = 29
Third question:
simplify in the parentheses 6 1/7 - 1/7 = 6
divide 60 by 6 to get 10
multiply 10 by 4 to get 40!
Fourth question:
simplify the fractions to get 1/3 + 8/3 = 3
multiply the 3 by 13 to get 39
