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3 years ago

7.

Mathematics

1 answer:

xeze [42]3 years ago

3 0

Answer: b. Side BC and Side KL

Step-by-step explanation:

Only these two lines are in the same positions.

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Tan(arcsin(x)) and its domain ...?

Mandarinka [93]

$- \frac{\pi}{2} < \arcsin{x} < \frac{\pi}{2} 
\\
\\\sin(- \frac{\pi}{2}) < \sin(\arcsin{x}) < \sin(\frac{\pi}{2} )
\\
\\-1 < x < 1$

6 0

3 years ago

a cone with a radius 3 units is shown below. it’s volume is 57 cubic units. find the height of the cone

ipn [44]

Given:

Given that the radius of the cone is 3 units.

The volume of the cone is 57 cubic units.

We need to determine the height of the cone.

Height of the cone:

The height of the cone can be determined using the formula,

$V=\frac{1}{3} \pi r^2 h$

Substituting the values, r = 3 and V = 57, we get;

$57=\frac{1}{3} (3.14) (3)^2 h$

Simplifying the terms, we get;

$57=\frac{1}{3} (3.14) (9) h$

Multiplying both sides of the equation by 3, we get;

$171= (3.14) (9) h$

$171=28.26 h$

Dividing both sides of the equation by 28.26, we get;

$6.05=h$

Thus, the height of the cone is 6.05 units.

8 0

3 years ago

What equation represents (0,3) (1, 1)

weqwewe [10]

your answer would be 2x - y + 3 = 0

3 0

2 years ago

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds a

kirill115 [55]

Answer:

12 feet per second.

Step-by-step explanation:

Please consider the complete question.

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be represented $h(t)=-16t^2+20t$ .

What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?

We will use average rate of change formula to solve our given problem.

$\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}$

$\text{Average rate of change}=\frac{h(\frac{1}{2})-h(0)}{\frac{1}{2}-0}$

$\text{Average rate of change}=\frac{-16\cdot(\frac{1}{2})^2+20\cdot \frac{1}{2}-(-16\cdot(0)^2+20\cdot (0))}{\frac{1}{2}-0}$

$\text{Average rate of change}=\frac{-16\cdot\frac{1}{4}+10-(0)}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{-4+10}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{6}{\frac{1}{2}}$

$\text{Average rate of change}=\frac{2\cdot 6}{1}$

$\text{Average rate of change}=12$

Therefore, Spot's average rate of ascent is 12 feet per second.

3 0

3 years ago

Two cards are chosen from a standard deck of 52 playing cards without replacement. What is the probability that the first card i

Rashid [163]

For the first draw, the probability of an ace is ( 4 / 52 ).

Now there are only 51 cards left in the deck.

For the second draw, the probability of a king is ( 4 / 51 ).

The probability of both events is

(4/52) (4/41) = (16/2,652)

Divide top and bottom by 4:

(16/2,652) = 4/663 . That's choice-C .

6 0

3 years ago