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weeeeeb [17]
3 years ago
15

-6y + 12 = - 66 I feel like I lost my brain today I can’t think right... can you help me out

Mathematics
2 answers:
Igoryamba3 years ago
6 0

Answer:

- 6y + 12 =  - 66 \\  - 6y =  - 66 - 12 \\  - 6y =  - 78 \\  y =  - \frac{ - 78}{ - 6}  \\ y =   13

professor190 [17]3 years ago
3 0

Answer:

y = 13

Step-by-step explanation:

i just solved this now, but I'm pretty sure it's correct :)

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Eric and Joshua are playing ping pong and pool. Joshua believes he has a good chance of beating Eric in at least one of the game
Sunny_sXe [5.5K]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Eric and Joshua are playing ping pong and pool. Joshua believes he has a good chance of beating Eric in at least one of the games. The probability Joshua beats Eric in ping pong is 0.48. The probability Joshua beats Eric in pool is 0.46. Joshua is willing to assume the probability of Eric winning a game of ping pong is independent of him winning a game of pool.

Find the probability:

The probability that Joshua beats Eric in ping pong AND pool?

The probability that Joshua beats Eric in ping pong OR pool?

Answer:

P(pp & pool) = 22%

There is 22% probability that Joshua beats Eric in ping pong AND pool.

P(pp OR pool) = 50%

There is 50% probability that Joshua beats Eric in ping pong OR pool.

Step-by-step explanation:

The probability Joshua beats Eric in ping pong is given by

P(pp) = 0.48

The probability Joshua beats Eric in pool is given by

P(pool) = 0.46

The probability that Joshua beats Eric in ping pong AND pool is given by

P(pp & pool) = P(pp)×P(pool)

P(pp & pool) = 0.48×0.46

P(pp & pool) = 0.22

P(pp & pool) = 22%

Therefore, there is 22% probability that Joshua beats Eric in ping pong AND pool.

The probability that Joshua beats Eric in ping pong OR pool is given by

P(pp OR pool) = P(pp)×0.52 + P(pool)×0.54

Where 0.52 is the probability that Eric beats Joshua in the ping pong match (1 - 0.48 = 0.52)

Where 0.54 is the probability that Eric beats Joshua in the pool match (1 - 0.46 = 0.54)

P(pp OR pool) = 0.48×0.52 + 0.46×0.54

P(pp OR pool) = 0.25 + 0.25

P(pp OR pool) = 0.50

P(pp OR pool) = 50%

Therefore, there is 50% probability that Joshua beats Eric in ping pong OR pool.

6 0
3 years ago
How do you simplify the radical expression, 24- sqrt(720 over 4
baherus [9]

24- sqrt(720/4) divide 720 by 4

24 - sqrt (180) now break down 180 to 9*4*5

24- sqrt(9) *sqrt(4) *sqrt (5)  so 9becomes 3, 4 becomes 2

24- 3*2*sqrt(5) multiply 3 and 2

24-6sqrt(5)

7 0
3 years ago
8.42 Three bags of jelly beans contain 26,28 , and 30 beans. In each bag, the percent of the beans that are yellow is 50%, 25%,
olasank [31]

Answer:

Step-by-step explanation:

Figure out the number of yellow beans in each bag:

Bag A: 0.5*26 = 13 beans

Bag B: 0.25*28 = 7 beans

Bag C: 0.2*30 = 6 beans

The total number of beans in the bowl: 26+28+30 = 84

Total number of yellow beans: 13+7+6 = 26

Percentage of yellow beans: 26/84 *100 = 30.9523

Rounded answer: 31%

6 0
2 years ago
Read 2 more answers
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Answer:

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3 0
3 years ago
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Use the distance formula to calculate the length of the leg CD
Karo-lina-s [1.5K]

To calculate the distance between two points on the coordinate system you have to use the following formula:

d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}

Where

d represents the distance between both points.

(x₁,y₁) are the coordinates of one of the points.

(x₂,y₂) are the coordinates of the second point.

To determine the length of CD, the first step is to determine the coordinates of both endpoints from the graph

C(2,-1)

D(-1,-2)

Replace the coordinates on the formula using C(2,-1) as (x₁,y₁) and D(-1,-2) as (x₂,y₂)

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The length of CD is √10 units ≈ 3.16 units

6 0
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