All categories

3 years ago

What is 7/200 as a decimal

Mathematics

1 answer:

Hitman42 [59]3 years ago

8 0

(7 / 2 ) / 100

3.5 / 100

0.035

So your answer is 0.035

You might be interested in

Explain why 4×3/5 equals 12 /5. draw a picture

BigorU [14]

Are you serious? oh well..

ok, draw a circle. devide the circle into 5 parts. color in 3 of the parts.

Now, draw 4 more of these.

Now, count the pieces.

4 0

3 years ago

1. Simplify: 2√50 × 3√32 × 4√18

kati45 [8]

2√50 × 3√32 × 4√18
=2(5√2) × 3(4√2)× 4(3√2)
=2(5)(2)(3)(4)(4)(3√2)
=2880√2

6 0

2 years ago

Read 2 more answers

Tobias rented a kayak from a sports equipment store.

Ket [755]

Answer:

Step-by-step explanation:

Let x = every day he rented the kayak

Since the store charges $60 for each day, multiply x by 60 like this: 60x

They also have $25 on top of that; 60x + 25

This all has to equal $325; 60x + 25 = 325

To solve for x, subtract 25 from both sides

60x + 25 = 325

- 25 - 25

60x = 300

Divide both sides by 60

60x/60 = 300/60

x = 5

This means Tobias rented the kayak for 5 days

7 0

2 years ago

6th grade math ! Help me pleaseee

Maksim231197 [3]

Answer:

$9.99

Step-by-step explanation:

To find the cost of 1 pizza pie, divide the total cost by 5

49.95 ÷ 5 = $9.99

3 0

2 years ago

Read 2 more answers

Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

<em>Second case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

4 0

3 years ago