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MArishka [77]
3 years ago
8

Where can you put parenthese so that the answer is correct 28-24/4•2=25

Mathematics
2 answers:
marysya [2.9K]3 years ago
8 0

Answer:

This really is about trial and error

28-24/(4*2)=25

Step-by-step explanation:

If you do this correctly, the numbers you'll get are 28-3 = 25!

Hope this helps!! :)

gtnhenbr [62]3 years ago
6 0

Answer:

I think this is the answer

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For each ordered pair, determine whether it is a solution to y=6.
Darya [45]

Answer:

yes

no

yes

no

if their is a 6 in the y spot of the coordinate than it is a yes

4 0
3 years ago
Find the perimeter and area of the following figure.<br> 10 ft<br> 5 ft<br> 8 ft<br> 3 ft
Mnenie [13.5K]

Answer:

33ft

Step-by-step explanation:

1. Work out the missing length.

2.10-3=7 so it is 7.

10+5+8+3+7=33ft

3 0
2 years ago
1. Alicia has 7 paintings she wants to hang side by side on her wall.
Kipish [7]

A.

If we take 7 paintings to be hung in 7 spaces side by side, the first space can have any one of the 7 paintings, the second space can have any one of the remaining 6 paintings (as 1 is already hung), the third space can have any one of the remaining 5 paintings (as 2 already hung)...It goes on like this.

So we have 7*6*5*4*3*2*1=5040 ways to arrange all the paintings from left to write. <em>(in factorial notation it is 7!=5040)</em>

B.

We use combinations rather than permutations because order doesn't matter. If we name the paintings A,B,C,D,E,F, and G, groups of 3 paintings of ABC or ACB are the same. So we evaluate 7C3 using the combination formula,

nCr=\frac{n!}{(n-r)!r!}

We have,

7C3=\frac{7!}{(7-3)!*3!} = \frac{7!}{4!*3!} = 35

C.

This is similar to part A in some ways. Any 3 pictures can be arranged in 3! different ways. 3!=3*2*1=6. So, 6 different ways.


ANSWER:

A) 5040 ways

B) 35 different groups

C) 6 ways

8 0
4 years ago
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The 123rd term of the sequence is 5
4 0
3 years ago
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Three collinear points on the coordinate plane are r(x,y), s(x+8h, y+8k), and p (x+6h, y+6k)
Karo-lina-s [1.5K]

Answer:

A.\frac{RP}{SP}=3

B.\frac{RP}{RS}=\frac{3}{4}

Step-by-step explanation:

<u><em>The complete question is</em></u>

Three collinear points on the coordinate plane are R(x, y), S(x+8h, y+8k), and P(x+6h, y+6k).

<em>Part A: Determine the value of RP/SP</em>

<em>Part B: Determine the value of RP/RS</em>

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

R(x,y),S(x+8h,y+8k) and P(x+6h,y+6k)

Part A.We have to find the value of \frac{RP}{SP}

step 1

Find the distance RP

R(x,y),P(x+6h,y+6k)

substitute the values in the formula

RP=\sqrt{(x+6h-x)^2+(y+6k-y)^2}

RP=\sqrt{36h^2+36 k^2}

RP=6\sqrt{h^2+k^2}

step 2

Find the distance SP

S(x+8h,y+8k),P(x+6h,y+6k)

substitute the values in the formula

SP=\sqrt{(x+6h-x-8h)^2+(y+6k-y-8k)^2}

SP=\sqrt{4h^2+4k^2}

SP=\sqrt{4(h^2+k^2)}

SP=2\sqrt{h^2+k^2}

step 3

<em>Find the ratio  RP/SP</em>

\frac{RP}{SP}=\frac{6\sqrt{h^2+k^2}}{2\sqrt{h^2+k^2}}

\frac{RP}{SP}=3

Part B. We have to determine the value of \frac{RP}{RS}

step 1

Find the distance RS

R(x,y),S(x+8h,y+8k)

RS=\sqrt{(x+8h-x)^2+(y+8k-y)^2}

RS=\sqrt{64h^2+64k^2}

RS=\sqrt{64(h^2+k^2)}

RS=8\sqrt{h^2+k^2}

step 2

<em>Find the ratio RP/RS</em>

\frac{RP}{RS}=\frac{6\sqrt{h^2+k^2}}{8\sqrt{h^2+k^2}}

\frac{RP}{RS}=\frac{3}{4}

5 0
3 years ago
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