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3 years ago

Where can you put parenthese so that the answer is correct 28-24/4•2=25

Mathematics

2 answers:

marysya [2.9K]3 years ago

8 0

Answer:

This really is about trial and error

28-24/(4*2)=25

Step-by-step explanation:

If you do this correctly, the numbers you'll get are 28-3 = 25!

Hope this helps!! :)

gtnhenbr [62]3 years ago

6 0

Answer:

I think this is the answer

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Hue is arranging chairs. She can form 2 rows of a given length with 4 chairs left over, or 8 rows of that

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7 Chairs in each row

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3 years ago

Helppp pleaseeeee The object below is made of solid plastic. It is a cylinder with an indentation at the top in the shape of a c

Jobisdone [24]

Answer:

Total volume = (145/3)π in³

Step-by-step explanation:

First find the volume of the entire cylinder. The correct formula to use here is:

V = πr²h, where r is the radius and h is the height. Here, with the radius being 5/2 inches and the height being 8 inches, the cylinder volume is

V = π(2.5 in)²(8 in) = 50π in³

Next find the volume of the conical shape: V = (1/3)π(2.5 in)²(0.8 in)

The desired volume is equal to the volume of the entire cylinder LESS the volume of the cone:

π(2.5 in)²(8 in) = 50π in³ LESS (1/3)π(2.5 in)²(0.8 in), which simplifies as follows:

Total volume =

50 π in³ - (1/3)π(2.5 in)²(0.8 in), or

(2.5 in)²π[8 in - 0.8/3 in] = π(6.25 in²)(8 in - 8/30 in) = π( 6.25 in²)(116/15 in), or

Total volume = (145/3)π in³

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3 years ago

Use properties to rewrite the given equation. Which equations have the same solution as 3/5x +2/3 + x = 1/2– 1/5x? Check all tha

vodomira [7]

we have

$\frac{3}{5}x+ \frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x$

Combine like terms in both sides

$(\frac{3}{5}x+ x)+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

we know that

$(\frac{3}{5}x+ x)=(\frac{3}{5}x+ \frac{5}{5}x)=\frac{8}{5}x$

substitute in the expression above

$\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$ -----> equation A

Multiply equation A by $5*3*2=30$ both sides

$30*(\frac{8}{5}x+\frac{2}{3})=30*(\frac{1}{2}-\frac{1}{5}x)$

$48x+20=15-6x$ ---------> equation B

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$48x+6x=15-20$

$54x=-5$ ---------> equation C

Solve for x

$x=-\frac{5}{54} =-0.09$

We are going to proceed to verify each case to determine the solution.

Case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

the case a) is equal to the equation A

the case a) have the same solution that the given equation

Case b) $18x+20+30x=15-6x$

Combine like terms in left side

$(18x+30x)+20=15-6x$

$(48x)+20=15-6x$

the case b) is equal to the equation B

the case b) have the same solution that the given equation

Case c) $18x+20+x=15-6x$

Combine like terms in left side

$(18x+x)+20=15-6x$

$(19x)+20=15-6x$

$19x+6x=15-20\\25x=-5\\x=-0.20$

$-0.20\neq -0.09$

therefore

the case c) not have the same solution that the given equation

Case d) $24x+30x=-5$

Combine like terms in left side

$54x=-5$

the case d) is equal to the equation C

the case d) have the same solution that the given equation

Case e) $12x+30x=-5$

Combine like terms in left side

$42x=-5$

$x=-5/42=-0.12$

$-0.12\neq -0.09$

therefore

the case e) not have the same solution that the given equation

therefore

the answer is

case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

case b) $18x+20+30x=15-6x$

case d) $24x+30x=-5$

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