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Mars2501 [29]
3 years ago
7

The quotient of 6 times a number and 16

Mathematics
2 answers:
Anettt [7]3 years ago
8 0
<span>The quotient of 6 times a number and 16 is </span>6x / 16


vfiekz [6]3 years ago
7 0
6x/16 
That is the answer to your question :).
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Solve the radical equation.<br> PLEASE HELPPPP
dusya [7]
This was taken from a source, but I hope it helped out! Have a nice day :)

(The answer is in the bottom of the picture)

3 0
3 years ago
Cristina bought a bag of coffee for $8.47. The weight of the bag was 7/8 of a pound. What was the price, per pound, of the coffe
SpyIntel [72]
~For this problem, you need to divide. 
~The easy way that I think might help you is if you change the fraction into a decimal. 
 
\frac{7}{8} = 0.875
  
Now divide $8.47 by 0.875
\frac{8.47}{0.875} = 9.68
     
     The price per pound of the coffee was $9.68

5 0
4 years ago
Read 2 more answers
Please help me this is for 95 points ​
uranmaximum [27]
Y=12
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7 0
2 years ago
Which expression is equivalent to (7x+9y)2
Arada [10]

Answer:

49x^2+126xy+81y^2

Step-by-step explanation:

Use the square of a binomial theorem

(a+b)^2= a^2+2ab+b^2

Now expand the given equation:

(7x+9y)^2=49x^2+126xy+81y^2

Hope this helps :)

Have a great day!

6 0
3 years ago
One person wants to get a 95% z-confidence interval with a margin of error of at most 15 based on a population standard deviatio
Bess [88]

Answer:

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=60 represent the population standard deviation  

n represent the sample size (variable of interest)  

Confidence =95% or 0.95

The margin of error is given by this formula:  

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

And on this case we have that ME =15, and we are interested in order to find the value of n, if we solve n from equation (1) we got:  

n=(\frac{z_{\alpha/2} \sigma}{ME})^2 (2)  

The critical value for 95% of confidence interval is provided, z_{\alpha/2}=1.96, replacing into formula (2) we got:  

n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62  

So the answer for this case would be n=62 rounded up to the nearest integer  

6 0
3 years ago
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