Answer:
KL = 10
Step-by-step explanation:
JK + KL = JL
2x – 2 + x – 9 = 2x + 8
Combine like terms
3x -11 = 2x+8
Subtract 2x from each side
3x-2x -11 = 2x+8-2x
x-11 = 8
Add 11 to each side
x-11+11 = 8+11
x = 19
KL = x – 9
= 19-9
= 10
Answer:
The new height of the water is 6.167 m
Step-by-step explanation:
The volume of the pool is given by the product of it's three dimensions width, length and height. In the initial situation we have a pool with width equals 4m, the length equals 6m and height of the water of 2m. So we can find the volume as seen bellow:
initial volume = length*width*height = 6*4*2 = 48 m^3
Then 100 m^3 were added to the pool, so it's new volume will be the sum of the initial volume and the added water so we have:
final volume = initial volume + 100 = 48 + 100 = 148 m^3
Since the only dimension that can change in this situation is the height ofthe water we can use the formula for the volume to find the new height, as seen below:
final volume = length*width*(new height)
148 = 6*4*(new height)
6*4*(new height) = 148
24*(new height) = 148
new height = 148/24 = 6.167 m
The new height of the water is 6.167 m
Answer:
The mean is 4.5
Step-by-step explanation:
u add the numbers and divide by how many numbers there are
Answer:
if it is multiple choice it's a bc I am on the same thing
The equation to be solved is: 3 [ 2 ^ (2t - 5) ] - 4 = 10
The steps are:
1) transpose - 4=> 3 [ 2^ (2t - 5) ] = 10 + 4
2) Combine like terms => 3 [2^ (2t - 5) ] = 14
3) Divide both terms by 3 => 2^ (2t - 5) = 14 / 3
4) Take logarithms of both sides => (2t - 5) log (2) = log (14/3)
5) Divide both sides by log (2) =>
log (14/3)
2t - 5 = -------------------
log (2)
6) transpose - 5+>
log (14/3)
2t = ------------------- + 5 = 2.22 + 5
log (2)
2t = 7.22
7) divide both sides by 2 => t = 7.22 / 2 = 3.61
