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3 years ago

What is the area of a rectangle with a length of (x - 5) and width of (x + 8)?

Mathematics

2 answers:

sashaice [31]3 years ago

6 0

Answer:

Step-by-step explanation:

dlinn [17]3 years ago

3 0

Answer:

a = x² + 3x - 40

Step-by-step explanation:

a = l * w

a = (x - 5)(x + 8)

a = x(x + 8) - 5(x + 8)

a = (x² + 8x) + (- 5x - 40)

a = x² + 3x - 40

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blsea [12.9K]

Option A: $\sqrt{75}$

Option C: $\sqrt{15} \cdot \sqrt{5}$

Option F: $\sqrt{25} \cdot \sqrt{3}$

Solution:

Given expression is $5 \sqrt{3}$ .

Option A: $\sqrt{75}$

$\sqrt{75}=\sqrt{25\times3}$

$=\sqrt{5^2\times3}$

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Hence $\sqrt{75}$ is equivalent expression of $5 \sqrt{3}$ .

Option B: $\sqrt{45}$

$\sqrt{45}=\sqrt{9\times5}$

$=\sqrt{3^2\times5}$

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Hence $\sqrt{45}$ is not equivalent expression of $5 \sqrt{3}$ .

Option C: $\sqrt{15} \cdot \sqrt{5}$

$\sqrt{15} \cdot \sqrt{5}=\sqrt{15\times5}$

$=\sqrt{75}$

$=5\sqrt{3}$ (proved in option A)

Hence $\sqrt{15} \cdot \sqrt{5}$ is equivalent expression of $5 \sqrt{3}$ .

Option D: $\sqrt{3} \cdot \sqrt{5}$

$\sqrt{3} \cdot \sqrt{5}=\sqrt{3\times5}$

$=\sqrt{15}$

Hence $\sqrt{3} \cdot \sqrt{5}$ is not equivalent expression of $5 \sqrt{3}$ .

Option E: 75

75 is a whole number.

Hence 75 is not equivalent expression of $5 \sqrt{3}$ .

Option F: $\sqrt{25} \cdot \sqrt{3}$

$\sqrt{25} \cdot \sqrt{3}=\sqrt{25\times3}$

$=\sqrt{75}$

$=5\sqrt{3}$ (proved in option A)

Hence $\sqrt{25} \cdot \sqrt{3}$ is equivalent expression of $5 \sqrt{3}$ .

Therefore, $\sqrt{75},\ \ \sqrt{15} \cdot \sqrt{5}, \ \ \sqrt{25} \cdot \sqrt{3}$ are all equivalent expressions of $5 \sqrt{3}$ .

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