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skelet666 [1.2K]
3 years ago
13

A 1-mile hiking path has signs placed every 240 feet. There are signs also placed at the beginning and end of the mile. How many

signs are there?
Mathematics
2 answers:
Fed [463]3 years ago
5 0

Answer:

22 or 24

Step-by-step explanation:

gtnhenbr [62]3 years ago
4 0

Answer:

yep 22

Step-by-step explanation:

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Solve using law of sines or law of cosines!
malfutka [58]

Answer:

Part 5) The length of the ski lift is 1.15\ miles

Part 6) The height of the tree is 18.12 m

Step-by-step explanation:

Part 5)

Let

A -----> Beginning of the ski lift

B -----> Top of the mountain

C -----> Base of mountain

we have

b=0.75\ miles

A=20\°

C=180\°-50\°=130\° ----> by supplementary angles

Find the measure of angle B

Remember that the sum of the interior angles must be equal to 180 degrees

B=180\°-A-C

substitute

B=180\°-20\°-130\°=30\°

Applying the law of sines

\frac{b}{sin(B)}=\frac{c}{sin(C)}

substitute

\frac{0.75}{sin(30\°)}=\frac{c}{sin(130\°)}

c=\frac{0.75}{sin(30\°)}(sin(130\°))

c=1.15\ miles

Par 6)

see the attached figure with letters to better understand the problem

<u><em>Applying the law of sines in the right triangle BDC</em></u>

In the right  triangle BDC 20 degrees is the complement of 70 degrees

\frac{BC}{sin(70\°)}=\frac{x}{sin(20\°)}

BC=(sin(70\°))\frac{x}{sin(20\°)} -----> equation A

<u><em>Applying the law of sines in the right triangle ABC</em></u>

In the right  triangle ABC 50 degrees is the complement of 40 degrees

\frac{BC}{sin(40\°)}=\frac{x+15}{sin(50\°)}

BC=(sin(40\°))\frac{x+15}{sin(50\°)} -----> equation B

Equate equation A and equation B and solve for x

(sin(70\°))\frac{x}{sin(20\°)}=(sin(40\°))\frac{x+15}{sin(50\°)}\\\\2.7475x=0.8391(x+15)\\\\2.7475x=0.8391x+12.5865\\\\2.7475x-0.8391x=12.5865\\\\x=6.60\ m

<u><em>Find the value of BC</em></u>

BC=(sin(70\°))\frac{6.6}{sin(20\°)}

BC=18.12\ m

therefore

The height of the tree is 18.12 m

5 0
4 years ago
The price of a stock decreased by $20\%$ in 2001, and then decreased by $20\%$ in 2002. What percent increase in 2003 will resto
Marysya12 [62]

oh come on

(read the comments(all of them))

7 0
3 years ago
Why do the functions f(x) = sin−1(x) and g(x) = cos−1(x) have different ranges?
Gnom [1K]
We Know that
For a function to have an inverse function, it must be one-to-one—that is, it must pass the Horizontal Line Test.

1. On the interval [–pi/2, pi/2], the function y = sin x is increasing
2. On the interval [–pi/2, pi/2], y = sin x takes on its full range of values, [–1, 1]
3. On the interval [–pi/2, pi/2], y = sin x is one-to-one
sin x has an inverse function on this interval [–pi/2, pi/2]

On the restricted domain [–pi/2, pi/2]  y = sin x has a unique inverse function called the inverse sine function. <span>f(x) = sin−1(x)
</span>the range of y=sin x  in the domain [–pi/2, pi/2]  is [-1,1] 
the range of y=sin-1  x  in the domain [-1,1]  is [–pi/2, pi/2]  

1. On the interval [0, pi], the function y = cos x is decreasing
2. On the interval [0, pi], y = cos x takes on its full range of values, [–1, 1]
3. On the interval [0, pi], y = cos x is one-to-one
cos x has an inverse function on this interval [0, pi]

On the restricted domain [0, pi]  y = cos x has a unique inverse function called the inverse sine function. f(x) = cos−1(x)
the range of y=cos x  in the domain [0, pi]  is [-1,1] 
the range of y=cos-1  x  in the domain [-1,1]  is [0, pi] 

the answer is

<span>the values ​​of the range are different because the domain in which the inverse function exists are different</span>  
8 0
3 years ago
What is There are fourteen whole snack bars on a plate. There are five friends.
AleksandrR [38]

Carl is incorrect. Dave ate a higher fraction of snack bars, by 0.2 snack bars.

Carl had .5 left of a snack bar.

Dave had .3 left of a snack bar.

Tony had .5 left of a snack bar.

Gary had .0 left of a snack bar.

Tryone had .7 left of a snack bar.

If we add the above snack bars, there is a total of two remaining snack bars, meaning they only ate 12 of 14 snack bars.

3 0
3 years ago
What is the constant rate of change from the graph ?
Anon25 [30]

Answer:

1/2

Step-by-step explanation:

rise/run, it goes up one (1/) and then right 2 (1/2)

4 0
3 years ago
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