Answer:
See explanation
Step-by-step explanation:
Consider two triangles ABF and EDF. These triangles are two right triangles, because angles B and D are right anges.
In these triangles,
- ∠ABF ≅ ∠EDF - as two right angles;
- BF ≅ FE - given;
- ∠AFB ≅ ∠EFD - as vertical angles when two lines AD and BE itersect.
By ASA postulate (or HA postulate) these triangles are congruent, so
ΔABF ≅ ΔEDF
Congruent triangles have congruent corresponding parts, so
FA ≅ EF
Answer:
I'm not able to do it but I can tell you how
Step-by-step explanation:
make the 10a-9 equal 14a-25 solve for that a then use the answer to a to then plug in thst number in all of them and that would be your answer
-|2x+3| > 2 and <span>-|2x+3| > - 2
</span>-2x+3 > 2
-2x > 2 - 3
-2x > -1
-2x / -2 > -1 / -2
x < 1/ 2
-|2x+3| > - 2
x < 5/2
Just divide it and you will get the answer
The answer is 5.
Step-by-step explanation:
To find the interquartile range you must look at the median and the upper and lower halves of the data. The median (12) to the upper half of the data (15) is 3. Next, look at the median (12) to the lower half of the data (10) it is 2. We then add 2 and 3 to get the interquartile range of 5.
