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Ymorist [56]
3 years ago
5

Evaluate C(3, 3) 1 6 24

Mathematics
1 answer:
Anestetic [448]3 years ago
4 0

Answer:

1

Step-by-step explanation:

Using the definition

nC_{r} = \frac{n!}{r!(n-r)!}

where n! = n(n - 1)(n - 2) × 3 × 2 × 1

and 0! = 1

3C_{3}

= \frac{3!}{3!(3 - 3)!}

= \frac{3!}{3!(0!)}

= \frac{3!}{3!} = 1

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