4 years ago

Evaluate C(3, 3) 1 6 24

Mathematics

1 answer:

Anestetic [448]4 years ago

4 0

Answer:

Step-by-step explanation:

Using the definition

n $C_{r}$ = $\frac{n!}{r!(n-r)!}$

where n! = n(n - 1)(n - 2) × 3 × 2 × 1

and 0! = 1

3 $C_{3}$

= $\frac{3!}{3!(3 - 3)!}$

= $\frac{3!}{3!(0!)}$

= $\frac{3!}{3!}$ = 1

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