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2 years ago

1) The height of a cylinder is 9 inches and the

Mathematics

1 answer:

Goshia [24]2 years ago

8 0

Answer:

Radius is ~2.26, Surface Area is ~159.89

IDK what you mean by 144(3.14), so I just used 144 as volume.

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(x2 - y2)-(-x2 + y2)<br> How do you write that out to show work ?! Help pleAse

Verdich [7]

Answer:

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do it or he will hunt you down and kill u (lets destroy the moderators!!!!!!!!)

we are slowing them down already! good work soilders!

Step-by-step explanation:

8 0

2 years ago

Solve the system of eqautions <br> y=x2-5x+7 , y=2x+1

IgorC [24]

Answer:

Step-by-step explanation:

The system of equations is given as

y=x^2-5x+7 - - - - - - - - - - 1

y=2x+1 - - - - - - - - - - - - - - 2

We would equate equation 1 to equation 2, it becomes

x^2-5x+7 = 2x+1

x^2-5x+7- 2x - 1 = 0

x^2 - 5x - 2x + 7 - 1 = 0

x^2 - 7x + 6 = 0

We would use the factorization method of solving quadratic equations.

x^2 - 6x - x + 6 = 0

x(x - 6) - 1(x - 6)

(x - 6)(x - 1) = 0

x - 6 = 0 or x - 1 = 0

x = 6 or x = 1

Substituting both values of x into equation 2, it becomes

For x = 6,

y=2×6 + 1 = 12 + 1 = 13

y = 13

For x = 1,

y=2 × 1 +1 = 2 + 1 = 3

y = 3

3 0

2 years ago

Clearly mark on the coordinate plane the location of the ordered pairs and

ladessa [460]

Answer:

Point $J(4,0)$ lies on $x-$ axis and point $M(-2,-3)$ lies quadrant III.

Step-by-step explanation:

A coordinate plane is a plane that is divided into four quadrants by the coordinate axes.

Here, coordinate axes are $x-$ axis and $y-$ axis.

Let's first mark the points in the coordinate plane.

See the attached figure.

From the figure, it can be observed that point $J(4,0)$ lies on $x-$ axis and point $M(-2,-3)$ lies quadrant III.

3 0

3 years ago

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0

3 years ago

Select the property of equality used to arrive at the conclusion. If x = 3, then x 2 = 3x

VARVARA [1.3K]

I think it would be the Multiplication property of equality

4 0

3 years ago

Read 2 more answers