I found width=13.72 ft and length=43.72 ft.
Call one dimension of the rectangle x, the other will be x+30
You want an area A=600 ft^2 but A=length x width=x*(x+30)=600
Rearranging you get:
![x^{2} +30x-600=0](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%2B30x-600%3D0)
solving this quadratic equation you get a negative solution and a positive one that gives your result.
Answer:
B) There will be no money in the safe 100 weeks after Lori learned the combination.
I hope this answer is right.
Answer:
the answer is 2
Step-by-step explanation: